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konstantin123 [22]
2 years ago
5

Identify three areas of energy research that scientists are working on today.

Chemistry
2 answers:
Illusion [34]2 years ago
3 0
Your answer would be Solar, Hybrid and wind. Hope this helps!
Jet001 [13]2 years ago
3 0

Answer:

wind, solar, bioproduction

Explanation:

The wind energy, since in some places the wind reaches fast velocities, the scientist try to implement new technology to improve how to convert wind energy in electricity for example.

The solar energy, even we have by now the solar panels, there is still an area to research to obtain again the mayor quantity of energy with less materials.

The bioproduction, since the mammals we produce liquid and solid wastes, how to convert it into energy like gas, electricity, etc.

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Water is moving across a membrane from solution a into solution
leva [86]

The answer is solution a must have a lower solute concentration than solution  b.

That is when water is moving across a membrane from solution a into solution b, then solution a must have a lower solute concentration than solution  b.

When solution a have a lower solute concentration than solution  b, then water moves across a membrane from solution a into solution b.

7 0
3 years ago
What are similarities between global warming and the greenhouse effect
n200080 [17]
The greenhouse effect is rightly called that because greenhouses allow heat to enter, but doesn't allow heat to leave, which warms plants.

On earth however, it's much bigger. Our own atmosphere acts similarly to this; it allows heat in, but doesn't allow it to leave which heats up the planet and causes global warming.
6 0
2 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
2 years ago
What elements is iodine made out of?
Thepotemich [5.8K]
Elements of iodine are fluorine, chlorine, bromine, and astatine.
8 0
3 years ago
HELP PLEASE
vodomira [7]

Answer:

4) how charged the object creating the field is and the distance between the two charged objects

3 0
2 years ago
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