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3 years ago

8

A patch of ground in direct sunlight will have ______ a patch of ground shaded by clouds.

2 answers:

Alexus [3.1K]3 years ago

4 0

Answer:

a lower air pressure (apex)

Explanation:

dlinn [17]3 years ago

3 0

<span>A patch of ground in direct sunlight will have a lower air pressure than a patch of ground shaded by clouds. It causes lower air pressure because as we move away from the surface amount of air will become less.Then Such changes could incorporate any of the different sorts of frosty front circumstances, storms or creating and propelling troughs of low weight, typically with going before cloud masses.</span>

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The power of a bulb is 100 watt .what does it mean

natita [175]

Answer:

Explanation: 100 watts is a unit of power.

A watt is also the amount of energy being consumed. So the more watts the brighter the light bulb is lit.

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3 years ago

An arcade ball is thrown with an initial speed of 7.0 m/s and follows the trajectory shown. The ball enter the basket .95 second

dmitriy555 [2]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

$x = 4.70 \ m$ , $y = 0.2803 \ m$

Explanation:

From the question we are told that

The initial velocity of the arcade ball is $u = 7.0 \ m/s$

The time taken by the ball to enter the basket is $t = 0.95 \ s$

Generally the x -component of the initial velocity is

$u_x = 7 * cos (45)$

=> $u_x = 4.95 \ m/s$

Generally the y -component of the initial velocity is

$u_x = 7 * sin(45)$

=> $u_y = 4.95 \ m/s$

Generally the distance x is mathematically represented as

$x = u_x * t$

=> $x = 4.95 * 0.95$

=> $x = 4.70 \ m$

Generally from kinematic equation the distance y is mathematically represented as

$y = u_y * t - \frac{1}{2} * g * t^2$

=> $y = 4.95 * 0.95 - \frac{1}{2} * 9.8 * 0.95^2$

=> $y = 0.2803 \ m$

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3 years ago

Momentum is mass times .

anzhelika [568]

Answer:True

Explanation:

4 0

3 years ago

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The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in

lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

$\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m$

or

$\tau=0.5\ N-m$

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

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4 years ago

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Tomtit [17]

I believe the correct answer is d. thermosphere.

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3 years ago

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