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Solnce55 [7]
3 years ago
8

A patch of ground in direct sunlight will have ______ a patch of ground shaded by clouds.

Physics
2 answers:
Alexus [3.1K]3 years ago
4 0

Answer:

a lower air pressure (apex)

Explanation:

dlinn [17]3 years ago
3 0
<span>A patch of ground in direct sunlight will have a lower air pressure than a patch of ground shaded by clouds. It causes lower air pressure because as we move away from the surface amount of air will become less.Then Such changes could incorporate any of the different sorts of frosty front circumstances, storms or creating and propelling troughs of low weight, typically with going before cloud masses.</span>
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A 15 kg mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the total work that must be done
sashaice [31]
Kinetic energy = (1/2) (mass) x (speed)²

At 7.5 m/s, the object's KE is (1/2) (7.5) (7.5)² = 210.9375 joules

At 11.5 m/s, the object's KE is (1/2) (7.5) (11.5)² = 495.9375 joules

The additional energy needed to speed the object up from 7.5 m/s
to 11.5 m/s is (495.9375 - 210.9375) = <em>285 joules</em>.

That energy has to come from somewhere. Without friction, that's exactly
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8 0
3 years ago
A silica-rich igneous rock that has large crystals and makes up much of the continental crust is ________
Oxana [17]
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6 0
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Name at least 4 other gases in the atmosphere besides oxygen and nitrogen
Irina18 [472]
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3 0
3 years ago
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Lorico [155]

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6 0
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You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to
earnstyle [38]

The correct answer to the question is : D) 352.6 m/s.

CALCULATION :

As per the question, the temperature is increased from 30 degree celsius to 36 degree celsius.

We are asked to calculate the velocity of sound at 36 degree celsius.

Velocity of sound is dependent on temperature. More is the temperature, more is velocity of sound.

The velocity at this temperature is calculated as -

                            V = 331  + 0.6T m/s

                               = 331 + 0.6 × 36 m/s

                               = 331 + 21.6 m/s

                               = 352.6 m/s.

Here, T denotes the temperature of the surrounding.

Hence, velocity of the sound will be 352.6 m/s.

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3 years ago
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