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Solnce55 [7]
3 years ago
8

A patch of ground in direct sunlight will have ______ a patch of ground shaded by clouds.

Physics
2 answers:
Alexus [3.1K]3 years ago
4 0

Answer:

a lower air pressure (apex)

Explanation:

dlinn [17]3 years ago
3 0
<span>A patch of ground in direct sunlight will have a lower air pressure than a patch of ground shaded by clouds. It causes lower air pressure because as we move away from the surface amount of air will become less.Then Such changes could incorporate any of the different sorts of frosty front circumstances, storms or creating and propelling troughs of low weight, typically with going before cloud masses.</span>
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What is the speed of terminal velocity?
ivann1987 [24]
The so-called "terminal velocity" is the fastest that something can fall
through a fluid.  Even though there's a constant force pulling it through,
the friction or resistance of plowing through the surrounding substance
gets bigger as the speed grows, so there's some speed where the resistance
is equal to the pulling force, and then the falling object can't go any faster.

A few examples:
-- the terminal velocity of a sky-diver falling through air,
-- the terminal velocity of a pecan falling through honey,
-- the terminal velocity of a stone falling through water.

It's not possible to say that "the terminal velocity is ----- miles per hour".
If any of these things changes, then the terminal velocity changes too:

-- weight of the falling object
-- shape of the object
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4 0
3 years ago
What group does paracetamol come under
agasfer [191]
Paracetamol is grouped within the 'painkillers' category. 
6 0
3 years ago
A hose directs a horizontal jet of water, moving with a velocity of 20m/s, on to a vertical wall. The
just olya [345]
Force is defined as the rate of change of momentum.
The initial amount of momentum is mv because water stops when it hit the wall total change of momentum must be \Delta p=mv.
Now let's calculate the force.
F= \frac{dp}{dt}=\frac{d(mv)}{dt}=\frac{dm}{dt}v
We need to find \frac{dm}{dt}. This is the amount of water hiting the wall per second.
\frac{dm}{dt}=\rho Av
Our final formula would be:
F=\rho Avv=\rho Av^2
And now we can calculate the answer:
F=1000\cdot5\cdot 10^{-4}\cdot(20)^2=200 N


6 0
3 years ago
A man pulls a 10 kg box at constant speed across the floor with a rope. The tension in the rope is 120 N at an angle of 30°.
Murrr4er [49]

Answer:

98n

Explanation:

5 0
2 years ago
6. A skier starts from rest at the top of a frictionless incline of height 20.0 m. At
n200080 [17]

Explanation:

a. KE at bottom = PE at top

½ mv² = mgh

v = √(2gh)

v = √(2 × 9.8 m/s² × 20.0 m)

v = 19.8 m/s

b. Work by friction = PE at top

mgμ d = mgh

d = h / μ

d = 20.0 m / 0.210

d = 95.2 m

6 0
3 years ago
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