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Semenov [28]
2 years ago
12

What is the unit of frequency

Physics
1 answer:
Phantasy [73]2 years ago
6 0

Answer:

hertz (Hz)

The number of periods or cycles per second is called frequency. The SI unit for frequency is the hertz (Hz).

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A pencil has a density of 0.875 g/ml. It has a volume of 4.0 ml. Find the mass
loris [4]

Answer:

To find the mass using density and volume we just multiply them against each other which causes ml to cancel and just leaves us with grams which represents how much the item weights.

mass=density*volume

mass=0.875\frac{g}{ml}*4.0\ ml

mass=3.5\ g

Therefore, our final answer is that our pencil weight 3.5 grams

<u><em>Hope this helps!  Let me know if you have any questions</em></u>

3 0
1 year ago
A person drives 70 km/h in 1 hour to the east, then 80 km/h for another hour to the east. What
andre [41]

Answer: The average velocity is 150 km/h

Explanation: 70+80=150

6 0
3 years ago
Amanda spent 2/5 of her time after school doing homework and ¼ of her remaining time riding her bike. If she rode her bike for 4
Doss [256]

Answer:120 min

Explanation:

Given

Amanda  spent \frac{2}{5} of her time after school doing Home work

And \frac{1}{4} of her remaining  time riding her bike

It is given that she rode her bike for 45 minutes in a week

Let t be the time after school

therefore Amanda spend \frac{2t}{5} in home work and  \frac{3t}{5} time is left

From remaining \frac{3t}{5} time she spends \frac{1}{4} time riding her bike

therefore \frac{3t}{5}\times \frac{1}{4}=45

thus t=300 min

therefore time  spent on home work is \frac{2}{5}\times 300=120 min

6 0
3 years ago
A certain spring stores 10.0J of potential energy when it isstretched by 2.00cm from its equilibrium position.How much potential
qaws [65]

Answer:

Answered

Explanation:

x= 0.02 m

E_p= 10.0 J

E_p= 0.5kx^2

10= 0.5k(0.02)^2

solving we get

K= 50.0 N/m

Now

E'_p= 0.5kx'^2

E'_p= 0.5×50×(0.04)^2

E'_p=40 J

b) potential energy is a scalar quantity and it only depends magnitude and not direction so it will remain same in compression and expansion both

c) 20 J = 0.5×50,000×x^2

solving

x= 0.028 m

d) k is 50.0 N/m  from above calculation

3 0
3 years ago
A 10 m long clothesline is strung so that it is perfectly horizontal. when a shirt is hung in the exact center the line sags to
Leto [7]

Answer:

x = 0.0873 m

Explanation:

given,

length of clothesline = 10 m

the line sags to create an angle that is 1 degree below the horizontal on each end.

As mass is hang at the center the angle made let the deflection be 'x'

as the shirt is hang at the center distance will be equal to 5 m.

now

tan \theta = \dfrac{d_e}{d}

tan \theta = \dfrac{x}{5}

tan 1^0 = \dfrac{W}{5}

W = 5 \times 0.0175

x = 0.0873 m

Hence, the cloth line will be x = 0.0873 m from the original length of the clothesline.

3 0
2 years ago
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