What is the molality of a solution made up of 43.6 mol of CACI₂ dissolved in 13.5 kg of water? Please Show work
1 answer:
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Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.
Solution : Given,
Mass of = 100 g
Molar mass of = 27 g/mole
Molar mass of = 28 g/mole
First we have to calculate moles of .
The given balanced chemical reaction is,
From the given reaction, we conclude that
2 moles of produced from 1 mole of
3.7 moles of produced from
of
Now we have to calculate the mass of .
Mass of = Moles of
× Molar mass of
Mass of = 1.85 mole × 28 g/mole = 51.8 g
Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.