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prohojiy [21]
2 years ago
8

What is the molality of a solution made up of 43.6 mol of CACI₂ dissolved in 13.5 kg of water? Please Show work

Chemistry
1 answer:
Llana [10]2 years ago
6 0

Answer:

The answer to your question is m = 3.2

Explanation:

Molality is defined as the number of moles of a solute dissolved in a mass of solvent (kg).

Data

moles of solute = 43.6

mass of solvent = 13.5 kg

Formula

Molality = \frac{number of moles}{Kg of solvent}

Substitution

Molality = \frac{43.6}{13.5}

Simplification and result

Molality = 3.2

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How many grams of sulfur are needed to react completely with 246 g of mercury to form hgs?
iren [92.7K]

The reaction between mercury (Hg) and sulfur (S) to form HgS is:

Hg + S ------------- HgS

Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS

The given mass of Hg = 246 g

Atomic mass of Hg = 200.59 g/mol

# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles

Based on the reaction stoichiometry,

# moles of S that would react = 1.226 moles

Atomic mass of S = 32 g/mol

Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g

39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS

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2 years ago
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alekssr [168]

Answer:

Most plastic is chemically inert and will not react chemically with other substances -- you can store alcohol, soap, water, acid or gasoline in a plastic container without dissolving the container itself.

Explanation:

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3 years ago
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A tank of gas is found to exert 8.6 atm at 38°C. What would be the required
Vesna [10]

Answer:

36.2 K

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 8.6 atm
  • Initial temperature of the gas (T₁): 38°C
  • Final pressure of the gas (P₂): 1.0 atm (standard pressure)
  • Final temperature of the gas (T₂): ?

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

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T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K

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A binary ionic compound is composed of ions of two different elements - one of which is a metal, and the other a nonmetal.

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3 years ago
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Suppose the half-life of element k is 20 minutes. if you have a 200 g sample of k, how much of element k will be left after 60 m
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T=20 min
m₀=200 g
t=60 min

the mass of element through time t is:
m=m₀*2^(-t/T)

m=200*2^(-60/20)=25 g

25 grams of element will be left after 60 minutes

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3 years ago
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