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Grace [21]
3 years ago
11

State what method you would use the separate water from a potassium iodide solution​

Chemistry
2 answers:
tia_tia [17]3 years ago
4 0

Answer:

<u>distillation</u> is the method used to separate water from a potassium iodine solution

Explanation:

hope it helps !!

Pachacha [2.7K]3 years ago
3 0

Answer:

You can separate the Iodine from the water and convert the potassium iodide into elemental Iodine by mixing 1 part of a 5–13% solution of Iodine/Potassium Iodide with 1 part distilled water and 1 part 3% Hydrogen Peroxide Solution followed by 1/12 part 32.45% hydrochloric (Muriatic) acid.

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4 years ago
How many atoms are there in 3 moles of Fe?
slamgirl [31]
N=N/Na
----. N=nxNa=3x6.023x10^23=<span>1.8069e+24</span>
7 0
3 years ago
If a pure compound is distilled, the head temperature will be____compared to the pot temperature. If however, an impurity is pre
shutvik [7]

Answer:

If a pure compound is distilled, the temperature of the head will be compared to the temperature of the pot. However, if there is an impurity present that strongly interacts with the molecules of the liquid, then the temperature must be increased to increase the vapor pressure of the liquid, eventually to atmospheric pressure, allowing the liquid to boil. Therefore, at the boiling point, the temperature of the pot will be higher than the temperature of the head.

Explanation:

when temperatures increase, pressures also do so, thus reaching boiling points where liquid states become gaseous.

4 0
3 years ago
Brainliest grind of 2014i-
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Explanation:

5 0
3 years ago
A 475 ml sample of a gas was collected at room temperature of 23.5 °C and a pressure of
Molodets [167]

Answer:

The volume when the conditions were altered is 0.5109 L or 510.9 mL

Explanation:

Using the general gas equation,

P1 V1 / T1 = P2 V2 / T2

where;

P1 = 756 mmHg

V1 = 475 ml = 0.475 L

T1 = 23.5°C = 23.5 + 273K = 275.5 K

P2 = 722 mm Hg

T2 = 10°C = 10 + 273 K = 283 K

V2 = ?

Rearranging to make V2 the subject of the formula, we obtain:

V2 = P1 V1 T2 / P2 T1

V2 = 756 * 0.475 * 283 / 722 * 275.5

V2 = 101, 625.3 / 198911

V2 = 0.5109 L or  510.9 mL

3 0
4 years ago
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