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3 years ago

if the mass of a material is 46 grams and the volume of the material is 5 cm^3 what would the density of the material be?

2 answers:

8 0

We use the following formula for calculating the density:

p = m/v

Where:
m = mass
v = volume

So, we have:

p = 46 /5
p = 9,2 g/cm³

Ipatiy [6.2K]3 years ago

7 0

Density = mass / volume

= 46 / 5

= 9.2 grams / cm^3

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3 years ago

A buffer is prepared by dissolving 0.80 moles of NH3 and 0.80 moles of NH4Cl in 1.00 L of aqueous solution. If 0.10 mol of NaOH

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Answer:

a. 10.54

Explanation:

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3 years ago

Good evening! Does anyone know this? Earth Science

riadik2000 [5.3K]

The fraction of Earth's radius (6371 km) relative to the thickness of the oceanic (7.5 km) and continental crust (35 km) is 0.12 and 0.55, respectively.

What we know:

The average radius of Earth (E) = 6371 km

The average thickness of oceanic crust (O) = 7.5 km

The average thickness of continental crust (C) = 35 km

We need to convert all the above units from kilometers to miles:

$E = \frac{0.6214 mi}{1 km}*6371 km = 3958.9 mi$

$O = \frac{0.6214 mi}{1 km}*7.5 km = 4.7 mi$

$C = \frac{0.6214 mi}{1 km}*35 km = 21.7 mi$

Now, we can calculate the fraction of Earth's radius relative to each type of crust, with the given equation:

$X = \frac{avg. \: thickness}{avg. \: radius} \times 100$

<u>For the oceanic crust (O)</u>:

$X = \frac{4.7 mi}{3958.9 mi}\times 100 = 0.12$

<u>For the continental crust (C)</u>:

$X = \frac{21.7 mi}{3958.9 mi}\times 100 = 0.55$

Therefore, the fraction of Earth's radius relative to the oceanic and continental crust is 0.12 and 0.55, respectively.

You can see another example of calculation of fractions of Earth's radius here: brainly.com/question/4675868?referrer=searchResults

I hope it helps you!

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