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dalvyx [7]
2 years ago
7

The below given compound is slightly soluble in water.

Chemistry
1 answer:
nordsb [41]2 years ago
4 0

Answer:

an alkali

Explanation:

an alkali is a base that is slightly soluble in water

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Which of the following statements is not true regarding molecular orbital theory? O Bonding molecular orbitals have lower energy
pychu [463]

Answer:

Option c, Two atomic orbitals combine to form one molecular orbital

Explanation:

Molecular orbitals are formed by linear combination of atomic orbitals.

Some of the important facts of molecular orbital theories are as follows:

  • No. of the molecular orbitals formed are equal to the no. of atomic orbitals participated.
  • Half of the molecular orbitals are bonding molecular orbitals and half of the molecular orbitals are anti bonding molecular orbitals.
  • Anti bonding molecular orbitals have energy higher than participating atomic orbitals.
  • Bonding molecular orbitals have energy lower than participating atomic orbitals.
  • Molecular orbitals are that region in the molecule where electrons are most likely to found.

So, among given, option c which is 'atomic orbitals combine to form one molecular orbital' is incorrect.

5 0
3 years ago
The pH of an unknown strong acid is 2. What<br> is the hydronium ion concentration?
MissTica

Answer: Finding the [H3O+] and pH of Strong and Weak Acid Solutions The larger the Ka, the stronger the acid and the higher the H+ concentration at equilibrium. hydronium ion, H3O+, 1.0, 0.00, H2O, 1.0×10−14, 14.00.

Explanation:The hydrogen ion in aqueous solution is no more than a proton, a bare ... the interaction between H+ and H2O .

8 0
3 years ago
Tell me What is an element?
Anarel [89]

Answer:

Any substance that cannot be decomposed into simpler substances by ordinary chemical processes.

Another definition:

An element is the simplest pure substance which can neither be split nor built up from other simpler substances by chemical reaction

5 0
2 years ago
Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.
Amanda [17]

Answer:

The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.

Explanation:

This problem is solve using rule of three

We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options

AM Sodium = 23 g

AM Chlorine = 35.5 g

                 Sodium                                     Chlorine

           23 g ---------------- 1 mol              35.5 g -------------- 1 mol

       1713.73g -------------    x               2666.6 g -------------    x

          x = 1713.73/23 = 74.51                     x = 2666.6/35.5 = 75.12

    These values are very similar, we have to look for the proportion in the options

a)      6.09g of sodium = 0.26 mol

      4,87 g of chlorine = 0.14 mol           These numbers are not very similar

b) We have 0.26 mol of Na

                  0.037 mol of Cl                      This is not the answer

c) We have 0.26 mol of Na

                  0.26 mol of Cl                     These numbers are the same, the proportion is 1:1, this is the answer

d) We have 0.26 mol of Na

                   0.36 mol of Cl                    This is not the answer

8 0
3 years ago
. How many milliliters of 0.20 M HCl are needed to exactly neutralize 40. milliliters of 0.40 M KOH
Anuta_ua [19.1K]

Answer:

V_{HCl}=80mL

Explanation:

Hello,

In this case, for the given reactants we identify the following chemical reaction:

KOH+HCl\rightarrow KCl+H_2O

Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:

n_{HCl}=n_{KOH}\\\\M_{HCl}V_{HCl}=M_{KOH}V_{KOH}

Hence, we compute the volume of HCl as shown below:

V_{HCl}=\frac{M_{KOH}V_{KOH}}{M_{HCl}} =\frac{0.40M*40mL}{0.20M} \\\\V_{HCl}=80mL

Best regards.

5 0
3 years ago
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