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dalvyx [7]
3 years ago
7

The below given compound is slightly soluble in water.

Chemistry
1 answer:
nordsb [41]3 years ago
4 0

Answer:

an alkali

Explanation:

an alkali is a base that is slightly soluble in water

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a person touch a large chunk of ice with their hands and remarks. this is making me cold explain wat this person felling. is the
k0ka [10]
There is both. the persons body heat transfers to the ice while the cold transfers off the ice to the persons hand. thats why when you hold and ice cube for a long enough time it melts because your body heat melts it, while at the same time your hand starts to get colder.

5 0
3 years ago
Which energy transformation occurs in an electric motor?
Hunter-Best [27]
I think the answer would be A ! Hope this helps
5 0
3 years ago
Under certain conditions the rate of this reaction is zero order in dinitrogen monoxide with a rate constant of ·0.0047Ms−1: 2N2
leva [86]

Answer:

250 mmol are left after 26.60 secs ≅ 26.6 seconds

Explanation:

zero order kinetics formula is:

[A] = [A₀] - kt

where [A] = amount left; [A₀] = amount remaining; k = rate constant; t = time

concentration [A₀] = mole/volume = 0.5 mole/2.0L = 0.25

[A] = 0.25 mole/2.0L = 0.125 M

k = 0.0047 Ms⁻¹

t = {[A]-[A₀]}/-k = (0.125 - 0.25)/(-0.0047) = 26.60 seconds = 26.6 seconds

the amount is reduced by half after 26.6 seconds

6 0
3 years ago
when reacting with Na with Cl2, we calculated that the theoretical yield should be 13.0 grams. our actual yield was 12.5 grams.
navik [9.2K]

Answer:

Percentage yield is 96.15%

Explanation:

Theoretical yield = 13.0g

Actual yield = 12.5g

Percentage yield = ?

Equation of reaction

2Na + Cl₂ → 2NaCl

Percentage yield = (actual yield / theoretical yield) * 100

Percentage yield = (12.5 / 13.0) * 100

Percentage yield = 0.9615 * 100

Percentage yield = 96.15%

Percentage yield of NaCl is 96.15%

3 0
3 years ago
The titration of 25.00 ml a 0.125 m hclo4 solution requires 27.07 ml of koh to reach the endpoint. what is the concentration of
agasfer [191]

Answer : The concentration of the KOH is, 0.115 M

Explanation :

Using dilution law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 1

n_2 = acidity of a base = 1

M_1 = concentration of HClO_4 = 0.125 M

M_2 = concentration of KOH = ?

V_1 = volume of HClO_4 = 25 ml

V_2 = volume of NaOH = 27.07 ml

Now put all the given values in the above law, we get the concentration of the KOH.

1\times 0.125M\times 25ml=1\times M_2\times 27.07ml

M_2=0.115M

Therefore, the concentration of the KOH is, 0.115 M

5 0
4 years ago
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