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hram777 [196]
3 years ago
10

Can anyone help with 5 through 8? Please :(

Chemistry
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

5)        Fe₂O₃(s)   +  3H₂O   ⇒    2Fe(OH)₃ (ac)        Synthesis reaction

6)        2C₄H₁₀(g)  + 13O₂(g)  ⇒   8CO₂ (g)  +  10H₂O   Combustion reaction

7)         2NO₂ (g)  ⇒   2O₂ (g)  +  N₂ (g)                     Decomposition reaction

8)         H₃P (g) +  2O₂ (g)  ⇒    PO (g)  +   3H₂O  Single replacement reaction

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What is the ph of a solution of 0.50 m acetic acid?
frosja888 [35]
You need to use the Ka for the acetic acid and the equilibrium equation.

Ka = 1.85 * 10^ -5

Equilibrium reaction: CH3COOH (aq) ---> CH3COO(-) + H(+)

Ka = [CH3COO-][H+] / [CH3COOH]

Molar concentrations at equilibrium

CH3COOH         CH3COO-     H+

 0.50  - x                  x                 x

Ka = x*x / (0.50 - x) = x^2 / (0.50 - x)

Given that Ka is << 1 => 0.50 >> x and 0.50 - x ≈ 0.50

=> Ka ≈ x^2 / 0.50

=> x^2 ≈ 0.50 * Ka = 0.50 * 1.85 * 10^ -5 = 0.925 * 10^ - 5 = 9.25 * 10 ^ - 6

=> x = √ [9.25 * 10^ -6] = 3.04 * 10^ -3 ≈ 0.0030

pH = - log [H+] = - log (x) = - log (0.0030) = 2.5

Answer: 2.5
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3 years ago
What is chemistry? I NEED HELP ASAP!
Thepotemich [5.8K]

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances.

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For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at
maw [93]

Answer:

2.55*10^{11

Explanation:

Equation for the heterogeneous system is given as:

2A_{(aq)}  + 3 B_{(g)} + C_{(l)}      ⇄      2D_{(s)}    +     3E_{(g)}

The concentrations and pressures at equilibrium  are:

[A] = 9.68*10^{-2}M

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[C]=14.64M

[D]=10.11M

P_E=9.56*10^4torr

If we convert both pressure into bar; we have:

P_B = 9.54*10^3Pa

P_B = (9.54*10^3)*\frac{1}{10^5} bar

P_B=9.54*10^{-2}bar

P_E=9.56*10^4torr

1 torr = 0.001333 bar

9.54*10^4 *0.001333 = 127.5 bar

K=\frac{[P_E]^3}{[A]^2[P_B]^3}

K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}

K=2.55*10^{11

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The resulting shape is a trigonal bipyramidal in which three fluorine atoms occupy equatorial and two occupy axial positions.

Learn more about PF5 here:

<h3>brainly.com/question/1565926</h3><h3 /><h3>#SPJ4</h3>
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