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Helen [10]
2 years ago
5

TRUE or FALSE

Chemistry
1 answer:
andriy [413]2 years ago
5 0

Answer:

1. true

2. false

3. true

Explanation:

You might be interested in
Molecules have Question 8 options: A) only kinetic energy. B) neither kinetic nor potential energy. C) only potential energy. D)
emmasim [6.3K]
The answer is C. only potential energy
6 0
3 years ago
PLEASE HELP ME UNDERSTAND...
mafiozo [28]

Three main particles form every atom. Protons and neutrons cluster in the nucleus at the center of the atom. Electrons form a spinning cloud around the nucleus. Protons and neutrons make up the mass of atoms. Electrons, miniscule compared to the protons and neutrons, contribute very little to the overall mass of atoms.

Atoms of the same element have the same number of protons. All copper atoms have 29 protons. All helium atoms have 2 protons. Isotopes occur when atoms of the same element have different masses. Since the number of protons of an element doesn't change, the difference in mass occurs because of different numbers of neutrons. Copper, for example, has two isotopes, copper-63 and copper-65. Copper-63 has 29 protons and a mass number of 63. Copper-65 has 29 protons and mass number 65. Helium has 2 protons and almost always has a mass number of 4. Very rarely, helium forms the isotope helium-3, which still has 2 protons but has a mass number of 3.

How Many Protons?

The atomic number on the Periodic Table identifies the number of protons in any atom of that element. Copper, atomic number 29, has 29 protons. Finding the atomic number of an element reveals the number of protons.

How Many Neutrons?

The difference between isotopes of an element depends on the number of neutrons. To find the number of neutrons in an isotope, find the mass number of the isotope and the atomic number. The atomic number, or number of protons, is found on the Periodic Table. The atomic mass, also found on the Periodic Table, is the weighted average of all the isotopes of the element. If no isotope is identified, the atomic mass can be rounded to the nearest whole number and used to find the average number of neutrons.

For example, the atomic mass of mercury is 200.592. Mercury has several isotopes with mass numbers ranging from 196 to 204. Using the average atomic mass, calculate the average number of neutrons by first rounding the atomic mass from 200.592 to 201. Now, subtract the number of protons, 80, from the atomic mass, 201-80, to find the average number of neutrons, 121.

If the mass number of an isotope is known, the actual number of neutrons can be calculated. Use the same formula, mass number minus atomic number, to calculate the number of neutrons. In the case of mercury, the most common isotope is mercury-202. Use the equation, 202-80=122, to find that mercury-202 has 122 neutrons.

How Many Electrons?

A neutral isotope has no charge, meaning that the positive and negative charges balance in a neutral isotope. In a neutral isotope, the number of electrons equals the number of protons. Like finding the number of protons, finding the number of electrons in a neutral isotope requires finding the atomic number of the element.

In an ion, an isotope with a positive or negative charge, the number of protons doesn't equal the number of electrons. If protons outnumber electrons, the isotope has more positive charges than negative charges. In other words, the number of protons exceeds the number of electron by the same number as the positive charge. If the number of electrons exceeds the number of protons, the ion charge will be negative. To find the number of electrons, add the opposite of the charge imbalance to the number of protons.

For example, if an isotope has a -3 charge, as with phosphorus (atomic number 15), then the number of electrons is three greater than the number of protons. Calculating the number of electrons then becomes 15+(-1)(-3) or 15+3=18, or 18 electrons. If an isotope has a +2 charge, as with strontium (atomic number 38), then the number of electrons is two less than the number of protons. In this case, the calculation becomes 38+(-1)(+2)=38-2=36, so the ion has 36 electrons. The usual shorthand for ions shows the charge imbalance as a superscript following the atomic symbol. In the phosphorus example, the ion would be written as P-3.

5 0
3 years ago
What do elements in the same group have? the same atomic mass the same number of electron shells similar properties similar atom
djyliett [7]
They all have the same number of electrons in their outer shell.
5 0
3 years ago
Read 2 more answers
You add 7.8 g of iron to 20.70 mL of water and observe that the volume of iron and water together is 21.69 mL . Calculate the de
bixtya [17]
21.69mL - 20.70mL = .99mL Fe
7.8 g / .99 mL = 7.9g/mL 
4 0
4 years ago
Pentaborane−9 (B5H9) is a colorless, highly reactive liquid that will burst into flames when exposed to oxygen. The reaction is
mote1985 [20]

Answer : The heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]

The equilibrium reaction follows:

2B_5H_9(l)+12O_2(g)\rightleftharpoons 5B_2O_3(s)+9H_2O(l)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(n_{(B_2O_3)}\times \Delta H^o_f_{(B_2O_3)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(B_5H_9)}\times \Delta H^o_f_{(B_5H_9)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]

We are given:

\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(5\times -1271.94)+(9\times -285.83)]-[(2\times 73.2)+(12\times 0)]=-9078.57kJ/mol

Now we have to calculate the heat released per gram of the compound reacted with oxygen.

From the reaction we conclude that,

As, 2 moles of compound released heat = -9078.57 kJ

So, 1 moles of compound released heat = \frac{-9078.57}{2}=-4539.28kJ

For per gram of compound:

Molar mass of B_5H_9 = 63.12 g/mole

\Delta H^o_{rxn}=\frac{-4539.28}{63.12}=-71.915kJ/g

Therefore, the heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

7 0
3 years ago
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