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Setler79 [48]
3 years ago
11

Isaac Newton experimented with prisms in 1666. What did his experiments show?

Physics
2 answers:
laiz [17]3 years ago
6 0
I know the answer it’s …
storchak [24]3 years ago
5 0

Answer:

hhgfyfyvghguvuhgcftfcgygyvguygvyt67dtuf

Explanation:

vgyc gghggvtgfvtifctttig7fcjti7jfctithcu6tchfufhtcufthcufchuftj

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Which of the following people challenged the geocentric model of the solar system?
Neporo4naja [7]
"Copernicus"was the one person among the following choices given in the question that <span>challenged the geocentric model of the solar system. The correct option among all the options that are given in the question is the second option. I hope that this is the answer that has come to your desired help.</span>
6 0
3 years ago
what is the magnitude of the electric force between charges of 0.25 C and 0.11 C at a separation of 0.88 m? if the separation be
leonid [27]
F = k \cdot \frac{q_1 q_2}{d} = 9 \cdot 10^{9} \cdot \frac{0.25 \cdot 0.11}{0.88} =  144 \cdot 5^{9} \ N.

If the separation between the charges is increased then the magnitude of the force will increase in fact how the distance is being used in that formula.
6 0
3 years ago
To what potential should you charge a 2.0 μF capacitor to store 1.0 J of energy?
Bess [88]
E = (1/2)CV²
1 = (1/2)*(2*10⁻⁶)V²
10⁶ = V²
1000 = V

You should charge it to 1000 volts to store 1.0 J of energy.
6 0
3 years ago
A force Fx=cx-3.00x2 acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c a consta
andrey2020 [161]

Answer:

4

Explanation:

We are given that

F_x=cx-3x^2

K.E at x=0 m=20 J

K.E at x=3 m=11 J

We have to find the value of c.

By work energy theorem

Work done=Change in kinetic energy

W=\int_{0}^{3} Fdx=\int_{0}^{3}(cx-3x^2)dx

W=[\frac{cx^2}{2}-x^3]^{3}_{0}

W=\frac{9c}{2}-27

\Delta K=11-20=-9 J

-9=\frac{9c}{2}-27

-9+27=\frac{9c}{2}

18=\frac{9c}{2}

c=\frac{2}{9}\times 18=4

4 0
3 years ago
Calculate the normal force pushing up from the table in each example 8 kg
garik1379 [7]

The correct answer to the question is: 78.4 N.

EXPLANATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the normal force of the object.

The object is resting on the table.

Hence, the object pushes the table downward with a force equal to it's weight.

The table, in turn, pushes the object with the same force as given by the object, but in the upward direction.

The force given by the table on the object is known as the normal reaction of the object which acts perpendicular to the surface of the object.

Hence, the normal reaction is equal to the weight of the body.

The weight of a body is the product of it's mass with acceleration due to gravity.

So, the weight of 8 Kg object is calculated as -

Weight = mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the normal force pushing up from the table is 78.4 N.







8 0
3 years ago
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