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Setler79 [48]
3 years ago
11

Isaac Newton experimented with prisms in 1666. What did his experiments show?

Physics
2 answers:
laiz [17]3 years ago
6 0
I know the answer it’s …
storchak [24]3 years ago
5 0

Answer:

hhgfyfyvghguvuhgcftfcgygyvguygvyt67dtuf

Explanation:

vgyc gghggvtgfvtifctttig7fcjti7jfctithcu6tchfufhtcufthcufchuftj

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_____ motion occurs when tectonic plates move apart from each other. A. Divergent B. Transform C. Convergent
Likurg_2 [28]
A. Divergent (pretty sure)
4 0
3 years ago
Read 2 more answers
A car travels along a highway with a velocity of 24 m/s, west. The car exits the highway; and 4.0 s later, its instantaneous vel
zloy xaker [14]

Answer:

4.25 m/s^{2}

Explanation:

Change in velocity considering the x component will be

Final velocity-Initial velocity

\triangle v_x= 16cos 45^{\circ}-24=-12.6862915 m/s

Change in velocity considering the y component will be

Final velocity-Initial velocity

\triangle v_y= 16sin 45^{\circ}-0=11.3137085 m/s

Resultant change in velocity=\sqrt {(-12.6862915 m/s)^{2}+(11.3137085 m/s)^{2}}=16.9982938 m/s

Acceleration= change in velocity per unit time hence

a= \frac {16.9982938}{4}=4.24957345\approx 4.25 m/s^{2}

5 0
3 years ago
An experimenter finds that standing waves on a string fixed at both ends occur at 24 Hz and 32 Hz , but at no frequencies in bet
Vera_Pavlovna [14]

Answer:

8 Hz

Explanation:

Given that

Standing wave at one end is 24 Hz

Standing wave at the other end is 32 Hz.

Then the frequency of the standing wave mode of a string having a length, l, is usually given as

f(m) = m(v/2L), where in this case, m could be 1. 2. 3. 4 etc

Also, another formula is given as

f(m) = m.f(1), where f(1) is the fundamental frequency..

Thus, we could say that

f(m+1) - f(m) = (m + 1).f(1) - m.f(1) = f(1)

And as such,

f(1) = 32 - 24

f(1) = 8 Hz

Then, the fundamental frequency needed is 8 Hz

4 0
3 years ago
On average, both arms and hands together account for 13% of a person's mass, while the head is 7.0% and the trunk and legs accou
Feliz [49]

Answer:

Angular velocity, N_f = 242.36 rpm

Explanation:

The mass of the skater, M = 74.0 kg

Mass of each arm, m_{a} = 0.13 * \frac{M}{2} ( since it is 13% of the whole body and each arm is considered)

m_{a} = 0.13 * 37\\m_a = 4.81 kg

Mass of the trunk, m_{t} = M - 2m_{a}

m_t = 74 - 2(4.81)\\m_{t} = 64.38 kg

Total moment of Inertia = (Moment of inertia of the arms) + (Moment of inertia of the trunks)

(I_{T} )_i = 2(\frac{m_{a}L^2 }{12} + m_a(0.5L + R)^2) + 0.5 m_t R^2

(I_{T} )_i = 2(\frac{4.81 * 0.7^2 }{12} + 4.81(0.5*0.7 + 0.175)^2) + 0.5 *64.38* 0.175^2\\(I_{T} )_i = 3.052 + 0.986\\(I_{T} )_i = 4.038 kgm^2

The final moment of inertia of the person:

(I_{T} )_f = \frac{1}{2} MR^{2} \\(I_{T} )_f = \frac{1}{2} * 74*0.175^{2}\\(I_{T} )_f = 1.133 kg.m^2

According to the principle of conservation of angular momentum:

(I_{T} )_i w_{i} = (I_{T} )_f w_{f}\\w_{i} = 68 rpm = (2\pi * 68)/60 = 7.12 rad/s\\4.038 * 7.12 =1.133* w_{f}\\w_{f} = 25.38 rad/s\\w_{f} = \frac{2\pi N_f}{60} \\25.38 = \frac{2\pi N_f}{60}\\N_f = (25.38 * 60)/2\pi \\N_f = 242.36 rpm

3 0
3 years ago
Vector B~ has x, y, and z components of 2.5, 3,
brilliants [131]

Answer:

magnitude:

formula: v=√(x)^2 + (y)^2 + (z)^2

√(2.5)^2 +(3)^2 + (7.8)^2

√76.09

=8.7

I hope this helped :)

7 0
3 years ago
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