Answer:
They are <em>directly proportional</em> to gravitational force.
Explanation:
Newton's Law of Gravity states that . The two "m" values are the masses of the objects, <em>r</em> is the distance between their centers, and G is the gravitational constant. Notice how the "m" values are in the fraction's numerator (i.e., on top)? That means <em>increasing</em> even one of the objects' masses will <em>increase</em> the gravitational force. This is known as a <em>direct relationship</em>.
Of course, you could always use the wonderful table provided to solve this! You don't believe what I wrote above? Take on of the two objects' masses, divide the gravitational force by that number, and see what happens. Multiply the two masses together, and see what happens. Prove it for yourself!
I hope this increases your understanding of this concept. Have yourself a wondrous day, 'kay?
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
Answer:
The pressure at this point is 0.875 mPa
Explanation:
Given that,
Flow energy = 124 L/min
Boundary to system P= 108.5 kJ/min
We need to calculate the pressure at this point
Using formula of pressure
Here,
Where, v = velocity
Put the value into the formula
Hence, The pressure at this point is 0.875 mPa
Answer:
Mustard is dicotyledon because it has 2 cotyledons in its seed.
Answer:
The horizontal component of the truck's velocity is: 23.70 m/s
The vertical component of the truck's velocity is: 3.13 m/s
Explanation:
You have to apply trigonometric identities for a right triangle (because the ramp can be seen as a right triangle where the speed is the hypotenuse), in order to obtain the components of the velocity vector.
The identities are:
Cosα=
Senα=
Where H is the hypotenuse, α is the angle, CA is the adjacent cathetus and CO is the opposite cathetus
The horizontal component of the truck's velocity is:
Let Vx represent it.
In this case, CA=Vx, H=24 and α=7.5 degrees
Vx=(24)Cos(7.5)
Vx=23.79 m/s
The vertical component of the truck's velocity is:
Let Vy represent it.
In this case, CO=Vy, H=24 and α=7.5 degrees
Vy=(24)Sen(7.5)
Vy=3.13 m/s