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SOVA2 [1]
3 years ago
6

In an aqueous chloride solution cobalt(ii) exists in equilibrium with the complex ion cocl42-. co2 (aq) is pink and cocl42-(aq)

is blue. ... at low temperature the pink color predominates. ... ... at high temperature the blue color is strong. ... if we represent the equilibrium as:... cocl42-(aq) co2 (aq) 4cl-(aq) we can conclude that: 1. this reaction is:
a. exothermic


b. endothermic


c. neutral


d. more information is needed to answer this question. 2. when the temperature is decreased the equilibrium constant, k:


a. increases


b. decreases


c. remains the same


d. more information is needed to answer this question. 3. when the temperature is decreased the equilibrium concentration of co2 :


a. increases


b. decreases


c. remains the same


d. more information is needed to answer this quest
Chemistry
1 answer:
liraira [26]3 years ago
5 0

First you should know that the Principle of Le Chatelier states that <u>if a system in equilibrium is subjected to a change of conditions, it will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium.</u>

The variation of one or several of the following factors can alter the equilibrium condition in a chemical reaction:

  • Temperature
  • The pressure
  • The volume
  • The concentration of reactants or products

1. This reaction is: <u>a. exothermic</u>

The chemical equilibrium at issue is:

CoCl₄²⁻  ⇄   Co²⁺ + 4Cl⁻ + heat

<em>blue</em>            <em>pink</em>

The reaction of the question is <u>exothermic</u> because when adding heat (at high temperature) the equilibrium moves to the left since the blue color is strong which means that there are more reagent (CoCl₄²⁻) that product (Co²⁺). On the other hand, when extracting heat from the system (at low temperature) the equilibrium moves to the right since the pink color predominates and more product is present in the solution.

2. When the temperature is decreased the equilibrium constant, k: <u>c. remains the same.</u>

As mentioned above, <u>a system in equilibrium that is disturbed will move to a new position in order to counteract the effect that disturbed it and recover the state of equilibrium. </u>In this way, the system will always remain in equilibrium and its equilibrium constant will remain constant. This is why, despite altering the temperature of the system, the equilibrium constant remains constant.

3. When the temperature is decreased the equilibrium concentration of Co²⁺:  <u>a. increases</u>

Again, the chemical equilibrium at issue is:

CoCl₄²⁻  ⇄   Co²⁺ + 4Cl⁻ + heat

As the reaction in question is exothermic when the temperature decreases, heat is extracted from the system. <u>To compensate this decrease in heat, the system will react by shifting the balance to the right, increasing the concentration of the products and, therefore, the concentration of Co²⁺.</u>

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Sloan [31]

Answer:

yes

Explanation:

8 0
3 years ago
A covalent bond between an oxygen atom and a hydrogen atom is best described as _____.
Igoryamba
The answer is most likely nonmetals. :)
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If this is a p1000 micropipette, then this is set to dispense [ Select]ul. If this is a p10
mariarad [96]

Answer:

1000 µL; 10 µL  

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A p1000 micropipet is set to dispense 1000 µL.

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3 years ago
What are the missing coefficents for the following equation? __N2+__H2-&gt;__NH3
vivado [14]

Answer:

1, 3, 2

Explanation:

N2 + H2 → NH3

I usually find that the best way to systematically balance an equation by inspection is to start with the most complicated-looking formula and then balance atoms in the order:

  1. All atoms other than O and H
  2. O
  3. H

(a) The most complicated formula is NH3.

(b) Balance N.

We have 1 H in NH3, but 2 N on the left. We need 2 N on the right. Put a 1 in front of N2 and a 2 in front of NH3.

1N2 + H2 → 2NH3

(c) Balance H.

We have fixed 6 H on the right, so we need 6 H on the left. Put a 3 in front of H2.

1N2 + 3H2 → 2NH3

The equation is now balanced, and the coefficients are 1, 3, 2.

5 0
3 years ago
Which of the following is NOT an exothermic reaction?
nignag [31]

Answer:

a) dissolving sugar in water to form a mixture of sugar and water

Explanation:

exothermic reaction is reaction in which is heat is released during the reaction and endothermic reaction is a reaction in which heat is needed or required for the reaction to take place

all the options excluding option A) is exothermic as during the process of formation of bonds in oxidation, heat is released. rusting too is a slow form of oxidation and thus an exothermic reaction.

dissolving sugar in water is not exothermic reaction because their is no heat released. the sugar molecules simply disperses in the water molecules and form a solution.

7 0
2 years ago
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