Answer: 1741289L
Explanation:
1 gallon = 3.78541 L
4.6×10^5 gallons = 4.6×10^5 x 3.78541 = 1741289L
metal rusting in salt water
Answer:
5.2 moles of KClO₃ are needed
Explanation:
Given data:
Number of moles of potassium chlorate needed = ?
Number of moles of O₂ formed = 7.8 mol
Solution:
Chemical equation:
2KClO₃ → 2KCl + 3O₂
now we will compare the moles of KClO₃ and O₂.
O₂ : KClO₃
3 : 2
7.8 : 2/3×7.8 = 5.2
5.2 moles of KClO₃ are needed.
Answer:
they keep the plastic bottles and make a Christmas decoration from it to use
Answer:
For more information about each chemical, view the safety data sheets. Click the Product Resources tab followed by Datasheet. You’ll need these materials: test tube rack test tubes (quantity: 6) test tube labels graduated cylinder wash bottle with distilled water (Tap water is acceptable, but it can skew the experimental results.) pipettes (quantity: 2) forceps 50-milliliter Erlenmeyer ask scoop test tube brush apron goggles gloves pen or re-tip marker small piece of sandpaper chemicals from Edmentum Lab kit: copper metal strip (quantity: 1) iron nails (quantity: 2) zinc metal strips (quantity: 3) copper(II) sulfate solution (10 milliliters) iron(III) nitrate solution (10 milliliters), also called ferric nitrate magnesium sulfate solution (10 milliliters) hydrochloric acid (30 milliliters) sodium bicarbonate (7.5 grams
Hope this helps
Explanation:
