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4vir4ik [10]
2 years ago
14

This wave, in total, is 30m. What is it's wavelength? * Your answer

Physics
2 answers:
Westkost [7]2 years ago
8 0

wavelength = d / number of Oscillation

this implies that wavelength = 30/3= 10

number of wavelengths = 10

Aleksandr-060686 [28]2 years ago
7 0

Answer:

Looking at the wave diagram

Its wavelength 3full wavelength which total to 30m...

So

3y = 30

y= 30/3

y=10meters

So a single wavelength is 10m.

Hope it helps

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Answer:

It will still hover until the spaceship "hits" or exerts a force on it.

Explanation:

Remember, if there is no net force, there is no acceleration or movement.

In this case, our ball is hovering in the spaceship, and in space, we can assume there is no F_g, and we can assume there is no F_N, nor no forces acting against it.

So, the ball would not move.

However, once the spaceship starts accelerating, the ball would still hover until the spaceship exerts a force on it.

This is because of the same thing as explained above, no forces acting on it, therefore, no acceleration.

Think about it this way.

Imagine you jumped up, then someone threw a ball at you. Now let's imagine you can't move until you hit the floor, meaning that in an ideal situation only  F_g is acting on you. Now again, let's imagine time slows really down for you, but not the ball. Before the ball comes and hits you, you are "hovering" like a ball. But after the ball hits you, you move a little because the ball exerted a force on you.

If you did not understand what I meant above, just forget about it, and think about the fact that if there is a Net force (all the force values added up), then there is acceleration and movement.

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1 year ago
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How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
soldi70 [24.7K]

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

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2 years ago
If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100
balu736 [363]

Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.  

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-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

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After the shot, the momentum of the cannonball is

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Divide each side by (5 kg):

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Speed of recoil of the cannon = <em>-- 0.4 m/s</em>

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