Answer:
1. the principle of original horizontality
2. the principle of crosscutting relationships
3. the law of superposition
4. older
5. younger
As the engine heats up, a natural circulation starts, as coolant rises through the engine block by convection. It passes through the top hose, and into the radiator. Inside the radiator, heat is removed from the coolant as it falls from the top to the bottom.
Hope this helps!
You are at rest with respect to the car.
You are in motion with respect to the School.
To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.
Where,
B = Magnetic Field
I = Current
L = Length
<em>Note: 
is a direct adaptation of the vector relation 
</em>
From Newton's second law we know that the relation of Strength and weight is determined as
Where,
m = Mass
g = Gravitational Acceleration
For there to be balance the two forces must be equal therefore
Our values are given as,
Diameter 
Radius 
Magnetic Field 
From the relationship of density another way of expressing mass would be
At the same time the volume ratio for a cylinder (the shape of the wire) would be
Replacing this two expression at our first equation we have that:
Re-arrange to find I
We have for definition that the Density of copper is 
, gravity acceleration is 
and the values of magnetic field (B) and the radius were previously given, then:
The current is too high to be transported which would make the case not feasible.
Answer:
a = 1.764m/s^2
Explanation:
By Newton's second law, the net force is F = ma.
The equation for friction is F(k) = F(n) * μ.
In this case, the normal force is simply F(n) = mg due to no other external forces being specified
F(n) = mg = 15kg * 9.8 m/s^2 = 147N.
F(k) = F(n) * μ = 147N * 0.18 = 26.46N.
Assuming the object is on a horizontal surface, the force due to gravity and the normal force will cancel each other out, leaving our net force as only the frictional one.
Thus, F(net) = F(k) = ma
26.46N = 15kg * a
a = 1.764m/s^2
