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andreev551 [17]
3 years ago
6

What are the Characteristics of handwriting?

Chemistry
2 answers:
mel-nik [20]3 years ago
5 0

Answer:

the specific shape of letters, e.g. their roundness or sharpness.

regular or irregular spacing between letters.

the slope of the letters.

the rhythmic repetition of the elements or arrhythmia.

the pressure to the paper.

the average size of letters.

the thickness of letters.

inna [77]3 years ago
4 0
Line quality: Examiners determine whether the letters flow in a smooth manner, or in an erratic or shaky way.

Spacing: Examiners determine whether the letters have equal spaces from each other or crowded.

Size consistency: Examiners check the consistency in terms of the ratio of the letter's height to its width.
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What is the smallest unit of an element that retains the properties of that element?
Temka [501]

Answer:

Atom

Explanation:

The smallest unit which maintains an element's properties is an atom.

3 0
3 years ago
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Calculate the mass of 29.8 mL of aluminum, which has a density of 2.00 g/mL.
MaRussiya [10]

Answer:

The answer is

<h2>59.6 g </h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

Density of aluminum = 2.00 g/mL

volume = 29.8 mL

The mass is

mass = 2 × 29.8

We have the final answer as

<h3>59.6 g</h3>

Hope this helps you

5 0
3 years ago
Heat required to raise 1 g of a substance 1°C
Oksana_A [137]

Answer:

Specific heat

Explanation:

7 0
3 years ago
Plz help soon? I’m confused
nata0808 [166]
Hi,
I think the answer is metric.
6 0
3 years ago
How many photons are produced in a laser pulse of 0.364 J at 477 nm?
Luda [366]

Answer:

1.00 × 10¹⁸

Explanation:

1. Calculate the <em>energy of one photon</em>

The formula for the energy of a photon is

<em>E</em> = <em>hc</em>/λ  

<em>h</em> = 6.626 × 10⁻³⁴ J·s; <em>c</em> = 2.998 × 10⁸ m·s⁻¹

λ = 477 nm = 477 × 10⁻⁹ m                              Insert the values

<em>E</em> = (6.626 × 10⁻³⁴ × 2.998× 10⁸)/(477 × 10⁻⁹)

<em>E</em> = 4.165× 10⁻¹⁹ J

2. Calculate the <em>number of photons</em>

Divide the total energy by the energy of one photon.

No. of photons = 0.418 × 1/4.165 × 10⁻¹⁹      

No. of photons = 1.00 × 10¹⁸

7 0
4 years ago
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