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3 years ago

7

Joaquin goes out for a long walk. He walks 5/12 of a mile and then sits down to take a rest. Then he walks 1/3 of a mile. How fa

r did Joaquin walk altogether?

1 answer:

Vsevolod [243]3 years ago

6 0

The answert to ur question is 3/4

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recycling one metric ton of corrugated cardboard will sAVE ABOUT 17 TREES. a WAREHOUSE RECYCLED 14,327 KILOGRAMS OF CORRUGATED C

slega [8]

1 kg = 0.001 metric tons..so 14327 kg = (14327 * 0.001) = 14.327 metric tons
and if 1 metric tons saves 17 trees....then 14.327 tons saves : 14.327 * 17 = 243.559 saved trees...and since u cant have 0.559 trees, u would round to 243 trees

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3 years ago

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What is the first step you should take to solve the following expression 2-16÷4×3(3+2)2+1

mestny [16]

The first step u should do is (3+2)

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3 years ago

A researcher is interested in estimating the mean weight of a semi trailer truck to determine the potential load capacity. She t

Kaylis [27]

Answer: 95% confidence interval = 20,000 ± 2.12 $\times$ $\frac{1500}{\sqrt{17} }$

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

Step-by-step explanation:

Given :

Sample size(n) = 17

Sample mean = 20000

Sample standard deviation = 1,500

5% confidence

∴ $\frac{\alpha}{2}$ = 0.025

Degree of freedom ( $d_{f}$ ) = n-1 = 16

∵ Critical value at ( 0.025 , 16 ) = 2.12

∴ 95% confidence interval = mean ± $Z_{c}$ $\times$ $\frac{\sigma}{\sqrt{n} }$

Critical value at 95% confidence interval = 20,000 ± 2.12 $\times$ $\frac{1500}{\sqrt{17} }$

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

3 0

3 years ago

What is the maximum percent of net spendable income that should be set aside for housing

stepladder [879]

Answer:

Answer;

-38 %

Step-by-step explanation:

Explanation;

-Budget busters are the large potential problem areas that can destroy a budget. Failure to control even one of these problem areas can result in financial disaster.

-Housing takes about 38 percent of your monthly budget. Housing decisions should be based on need and financial ability, not on internal or external pressure.

-Food takes 12 percent of your monthly budget. The reduction of a family's food bill requires quantity and quality planning.

-Transportation (purchase and maintenance), takes 15 percent of your monthly budget, Debts takes 5 percent of Net Spendable Income, Insurance takes 5 percent of Net Spendable Income assuming an employer provides medical insurance, Recreation/Entertainment takes 5 percent of Net Spendable Income, Clothing takes 5 percent of Net Spendable Income, Medical and dental takes 5 percent of Net Spendable Income and Savings takes 5 percent of Net Spendable Income

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3 years ago

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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

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3 years ago