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butalik [34]
3 years ago
15

The cycling of the air is a natural phenomenon as shown above is the result of

Physics
2 answers:
Ket [755]3 years ago
6 0

Answer:

natural convection

............

Taya2010 [7]3 years ago
6 0
Natural conviction hope this helps!
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The truck in which
sertanlavr [38]

Answer:

m = 4

Explanation:

We have,

You apply a force of  600 N to the branch  which acts as a lever. It means it is input force, IF = 600 N

The rear of the truck  weighs 2,400 N. It means it is output force, OF = 2400 N

The ratio of output force to the input force is equal to the mechanical advantage of the lever arm. It is given by :

m=\dfrac{2400}{600}\\\\m=4

So, the mechanical  gain of the lever arm is 4.

8 0
3 years ago
A sinusoidal transverse wave travels along a long, stretched string. The amplitude of this wave is 0.08190.0819 m, its frequency
Anvisha [2.4K]

Answer:

The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.

Explanation:

Given that,

Amplitude = 0.08190 m

Frequency = 2.29 Hz

Wavelength = 1.87 m

(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave

Using formula of distance

d=2A

Where, d = distance

A = amplitude

Put the value into the formula

d=2\times0.08190

d=0.1638\ m

Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.

5 0
3 years ago
The tires on your truck have 0.35 m radius. In a straight line, you drive 2600 m. What is the angular displacement of the tire,
Travka [436]
1) In a circular motion, the angular displacement \theta is given by
\theta =  \frac{S}{r}
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire: S=2600 m. Using the information about the radius, r=0.35 m, we find the total angular displacement:
\theta =  \frac{2600 m}{0.35 m} =7428 rad

2) If we put larger tires, with radius r=0.60 m, the angular displacement will be smaller. We can see this by using the same formula. In fact, this time we have:
\theta =  \frac{2600 m}{0.60 m}=4333 rad
8 0
4 years ago
Pls help. This is about heat. I got the answer, just need the working
Mars2501 [29]

Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C  from 20 C

  this will take   .20 kg *    390 j /kg-C   *  80 C = <u>6240 j</u>

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take    

    .50 kg * 4182 j/kg-C  * 80 = <u>167,280 j </u>

AND you have to add enough heat to boil off  .03 kg of water:

   .03 kg * (2260000 j/kg-C )  =<u> 67,800 j</u>

<u />

Power = joules / sec =  (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>

<u />

<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>

7 0
2 years ago
The diagram below shows different weights on the see-saw. Will the see-saw move?
oee [108]

Answer:

yes it will

Explanation:

8 0
3 years ago
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