What is the pH when [H+] = 0.000032 M?

Write the Formulas for these ionic compounds:

Alinara [238K]

Answer:

<h2>1. Tin(IV) oxide</h2>

Tin(IV) oxide, also known as stannic oxide, is the inorganic compound with the formula SnO₂. The mineral form of SnO₂ is called cassiterite, and this is the main ore of tin. With many other names, this oxide of tin is an important material in tin chemistry. It is a colourless, diamagnetic, amphoteric solid.

Formula: SnO₂

Molar mass: 150.71 g/mol

Melting point: 1,630 °C

Density: 6.95 g/cm³

<h2>2. Aluminum oxide</h2>

Aluminium oxide is a chemical compound of aluminium and oxygen with the chemical formula Al₂O₃. It is the most commonly occurring of several aluminium oxides, and specifically identified as aluminium(III) oxide.

Formula: Al₂O₃

Molar mass: 101.96 g/mol

Melting point: 2,072 °C

Density: 3.95 g/cm³

Boiling point: 2,977 °C

ChemSpider ID: 14086

ChemSpider ID: 26988

<h2>3. Silver sulfide</h2>

Silver sulfide is an inorganic compound with the formula Ag ₂S. A dense black solid, it is the only sulfide of silver. It is useful as a photosensitizer in photography. It constitutes the tarnish that forms over time on silverware and other silver objects.

Formula: Ag2S

Molar mass: 247.8 g/mol

Density: 7.23 g/cm³

ChemSpider ID: 145878

<h2>4. Copper (II) sulfate</h2>

Copper(II) sulfate, also known as copper sulphate, are the inorganic compounds with the chemical formula CuSO₄ₓ, where x can range from 0 to 5. The pentahydrate is the most common form. Older names for this compound include blue vitriol, bluestone, vitriol of copper, and Roman vitriol.

Formula: CuSO4

IUPAC ID: Copper(II) sulfate

Molar mass: 159.609 g/mol

Density: 3.6 g/cm³

Melting point: 110 °C

Soluble in: Water

<h2>5. Potassium carbonate</h2>

Potassium carbonate is the inorganic compound with the formula K₂CO₃. It is a white salt, which is soluble in water. It is deliquescent, often appearing as a damp or wet solid. Potassium carbonate is mainly used in the production of soap and glass.

Formula: K2CO3

Molar mass: 138.205 g/mol

IUPAC ID: Potassium carbonate

Density: 2.43 g/cm³

Melting point: 891 °C

Soluble in: Water

Explanation:

Hope it is helpful....

4 0

2 years ago

Which of the following solutions is acidic? [H3O+] = 1.0 x 10-10 M [H3O+] < 1.0 x 10-7 M [OH-] = 1.0 x 10-10 M [OH-] = 1.0 x

Burka [1]

Answer:

[OH-] = 1.0 x 10-10 M

Explanation:

The acidity of a solution can be determined directly from the concentration of the hydrogen ions and indirectly from the concentrations of the hydroxide ions.

Generally, for a neutral solution we have;

[H3O+] = [OH-] = 1.0 x 10-7 M

For an acidic solution;

[H3O+] > 1.0 x 10-7 M

[OH-] < 1.0 x 10-7 M

Comparing the options the correct option is;

[OH-] = 1.0 x 10-10 M

6 0

3 years ago

Isotopes: are atoms of different elements which have the same mass are atoms of the same element with equal numbers of neutrons

koban [17]

I can't understand your option because there is no full stop however

isotopes are 2 or more form of elements that contain equal number of proton but different number of neutron in their nuclei

4 0

3 years ago

Read 2 more answers

Ne4ueva [31]

Answer:

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

Explanation:

Volume of cylindrical reservoir = V

Radius of the cylindrical reservoir = r = d/2

d = diameter of the cylindrical reservoir = d = $4.50\times 10^1 m=45 m$

r = d/2 = 22.5 m

Depth of the reservoir = h = 10.0 m

$V=\pi r^2 h$

$=3.14\times (22.5 m)^2\times 10.0 m=15,896.25 m^3=15,896,250 L$

$1 m^3=1000 l$

Volume of water cylindrical reservoir : V

Density of water,d = 1 kg/L

Mass of water cylindrical reservoir = m

$m=d\times V=1 kg/L\times 15,896,250 L=15,896,250 kg$

1.6 kilogram of fluorine per million kilograms of water. (Given)

Concentration of fluorine in water = 1.6 kg/ 1000,000 kg of water

In 1000,000 kg of water = 1.6 kg of fluorine

Then $15,896,250 kg$ of water have x mass of fluorine:

$\frac{x}{15,896,250 kg\text{kg of water}}=\frac{1.6 kg}{1000,000 \text{kg of water}}$

$x=\frac{1.6 kg}{1000,000}\times 15,896,250 kg=25.434 kg$

15,896,250 kg water of contains mass 25.434 kg of fluorine.

25.434 kg = 25434 g

25,434 grams of fluorine should be added to give 1.6 ppm.

Percentage of fluorine in hydrogen hexafluorosilicate :

Molar mass hydrogen hexafluorosilicate = 144 g/mol

$F\%=\frac{6\times 19 g/mol}{144 g/mol}\times 100=79.16\%$

Total mass of hydrogen hexafluorosilicate = m'

$79.16\%=\frac{25,434 g}{m'}\times 100$

m' = 32,127.02 g

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434 grams of F.

5 0

3 years ago

A biochemical reaction will proceed in the direction as written if:_______a. ΔG > 0.b. ΔH > 0.c. ΔG = zero.d. ΔG < 0.e.

garik1379 [7]

Answer:

ΔG < 0

Explanation:

The condition for spontaneity of a chemical reaction is that ∆G<0. Hence for any biochemical reaction to proceed as written, ∆G must have a negative value.

If ∆G >0, the reaction is not spontaneous and will not proceed as written. ∆G=0 means that the reaction has attained equilibrium.

5 0

3 years ago