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2 answers:
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Answer:
1. was the
value calculated by the student.
2. was the
of ethylamine value calculated by the student.
Explanation:
1.
The value of Aspirin solution = 2.62
Moles of s asprin =
Volume of the solution = 0.600 L
The initial concentration of Aspirin = c =
initially
c 0 0
At equilibrium
(c-x) x x
The expression of dissociation constant :
:
was the
value calculated by the student.
2.
The value of ethylamine = 11.87
The initial concentration of ethylamine = c = 0.100 M
initially
c 0 0
At equilibrium
(c-x) x x
The expression of dissociation constant :
:
was the
of ethylamine value calculated by the student.