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3 years ago

A catalyst:

Chemistry

2 answers:

svetlana [45]3 years ago

4 0

Answer:

Catalyst decreases activation energy

Explanation:

Consider the attached diagram and note the annotation => top of transition diagram for catalyzed reaction is lower than uncatalyzed reaction.

posledela3 years ago

3 0

Answer:

Explanation:

well, just need to remember

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

Scorpion4ik [409]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.

Explanation:

Step 1 : Calcium carbide and water react to form acetylene and calcium hydroxide

$CaC_2(s)+2H_2O(g)\rightarrow$

$C_2H_2(g)+Ca(OH)_2(s),\Delta H_1=-414 kJ$ ..[1]

Step 2 : Acetylene, carbon dioxide and water react to form acrylic acid

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCOOH(g),\Delta H_2=132 kJ$ ..[2]

Using Hess's law:

[1] × 6 + [2]

$6CaC_2(s)+16H_2O(g)+3CO_2\rightarrow 5CH_2CHCOOH(g)+6Ca(OH)_2(s),\Delta H_3=?$

$\Delta H_3=6\times \Delta H_1+\Delta H_2$

$\Delta H_3=6\times (-414 kJ)+132 kJ=-2352 kJ$

The energy released on formation of 5 moles of acrylic acid = -2352 kJ

The energy released on formation of 1 moles of acrylic acid :

$=\frac{-2352 kJ}{5 mol}=-470.4 kJ/mol$

Hence, the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is -470.4 kJ/mol.

5 0

2 years ago

En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L

love history [14]

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

$Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}$

Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

Donde X representa el avance de reacción.

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

Resolviendo para X:

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = 15.454atm

P I₂: X = 0.923atm

P Br₂: X = 0.923atm

3 0

2 years ago

Read 2 more answers

Complete the paragraph about the formation of sodium phosphide.

Nadya [2.5K]

<h2>Let us complete it :</h2>

Explanation:

let us study about formation of sodium phosphide

Electrons are transferred from atoms of sodium to atoms of phosphorous

The sodium atom looses electrons and the phosphorus atoms

gains electrons .

C. This transfer makes the sodium atoms acquire positive charge and phosphorous acquire negative charge .

As a result, the sodium and phosphorus atoms strongly bond with

each other.

8 0

2 years ago

An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams

tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0

3 years ago

With respect to a fixed point, motion is defined as a change in- A)speed B)position

Arisa [49]

Answer:

With respect to a fixed point, motion is defined as a change in position.

Explanation:

MOTION -: Motion is described as the fact in which any object or body changes its position over the time with respect to a fixed point .

Motion is defined as displacement, distance, velocity , acceleration, speed , and time in mathematical terms. By linking an observer to a frame of reference and measuring the shift in the position of the body with a change in time relative to that frame, the motion of a body is observed.

4 0

2 years ago