Answer: I believe his brother, Mike, who is 6'2, will have the longer shadow.
Given:
Height of tank = 8 ft
and we need to pump fuel weighing 52 lb/
to a height of 13 ft above the tank top
Solution:
Total height = 8+13 =21 ft
pumping dist = 21 - y
Area of cross-section =
=
=16

Now,
Work done required = 
= 
= 832
)
= 113152
= 355477 ft-lb
Therefore work required to pump the fuel is 355477 ft-lb
<span>Solar prominences
themselves are of no concern because they are visible in the Hydrogen Alpha
wavelength. They are anchored in place by magnetic fields. When these fields
break or reconnect, it can send the plasma that makes up the prominence away
from the sun. If one of these clouds impacts Earth, they are called CMEs or
coronal mass ejections. Depending on the magnetic orientation of the cloud with
respect to Earth's the CME can break down our magnetic field resulting in
geomagnetic storms, aurorae, power grid fluctuations, and particle radiation
near the poles, satellite single upset events, and radio blackouts. </span>
<span>
</span>
<span>Thus, letter a is the answer. </span>
Answer:
≅279.02 N, 36° 15' from North to East
Explanation:
You can the theory of triangle of forces to find the answer.
Two forces are acting perpendicular to each other so use Pythagoras theorem to find the magnitude of the resultant force(x).
x² = 225² + 165²
x = 279.02 N
To find the direction use the same force triangle,
Workings are in the attachment,