F = force applied to stop the car = - 3000 N
m = mass of the car = 3000 kg
a = acceleration of the car = ?
v₀ = initial velocity of the car before the force is applied to stop it = 10 m/s
v = final velocity of the car when it comes to stop = 0 m/s
d = stopping distance of the car
acceleration of the car is given as
a = F/m
inserting the values
a = - 3000/3000
a = - 1 m/s²
using the kinematics equation
v² = v²₀ + 2 a d
inserting the values
0² = 10² + 2 (-1) d
0 = 100 - 2 d
2 d = 100
d = 100/2
d = 50 m
hence the correct choice is
C. 50 m
Could be c because it matches the question
To answer this question, it helps enormously if you know
the formula for momentum:
Momentum = (mass) x (speed) .
Looking at the formula, you can see that momentum is directly
proportional to speed. So if speed doubles, so does momentum.
If the car's momentum is 20,000 kg-m/s now, then after its speed
doubles, its momentum has also doubled, to 40,000 kg-m/s.
<span>v=40 <span><span>cm</span>s</span> speed of wave</span>
<span>λ=8 cm wavelength</span>
<span>f=? frequency of wave</span>
<span>v=λ⋅f</span>
<span>40=8⋅f</span>
<span>f=<span>408</span></span>
<span>f=5 <span>s<span>−<span>1 is the answer </span></span></span></span>
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