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9966 [12]
3 years ago
6

Which type if energy is used to power your tv?

Physics
2 answers:
Ghella [55]3 years ago
6 0

Answer:

electrical energy powers your TV, computer, microwave and toaster.

Murrr4er [49]3 years ago
5 0

Answer:

electrical

Explanation:

the TV needs electrical energy to power on

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Romashka-Z-Leto [24]

Answer:

Obviously the answer is Sun...

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3 years ago
Do you like genetic engineering explain even if there is no answer box still answer in the commets
liubo4ka [24]

Answer:

yes it is so awesome

Explanation:

4 0
3 years ago
Calculate the amount of heat (in kJ) required to convert 97.6 g of water to steam at 100° C. (The molar heat of vaporization of
Ratling [72]

Answer:

221.17 kJ

Explanation: Note the heat of vaporization is in kJ/mol,then to determine the number of moles of water: divide the mass by 18. Then multiply the number of moles by the molar heat of vaporization of water.

N = 97.6 ÷ 18

Q=molar heat *moles

Q = (40.79) * (97.6 ÷ 18)

This is approximately 221.17 kJ

4 0
2 years ago
An airplane with constant speed 696 mph than another 40 minutes constant speed 804 mph what is distance it go?
sleet_krkn [62]

Answer:

536 miles

Explanation:

If the airplane is running at a speed of 804 miles per hour, and covers a distance, x in a particular number of mile. The distance in mile can be gotten they the application of direct formula. Multiplying the speed by the time it took, and thus

804 mph * 40

Remember the time is in minutes and not hours, so, you convert it to hours.

804 * 40/60 hours =

536 miles

6 0
3 years ago
A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab (Fig. 6-58). The coefficient of static fricti
vovikov84 [41]

Answer:

<u>\text { The "resulting action" on the slab is } 0.98 \mathrm{m} / \mathrm{s}^{2}</u>

Explanation:

Normal reaction from 40 kg slab on 10 kg block

M × g  = 10 × 9.8 = 98 N  

Static frictional force = 98 × 0.7 N

Static frictional force = 68.6 N is less than 100 N applied  

10 kg block will slide on 40 kg slab and net force on it  

= 100 N - kinetic friction  

=100-(98 \times 0.4)\left(\mu_{\text {kinetic }}=0.4\right)

= 100 - 39.2

= 60.8 N

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with, } \frac{\mathrm{Net} \text { force }}{\text { mass }}

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with }=\frac{60.8}{10}

10 \mathrm{kg} \text { block will slide on } 40 \mathrm{kg} \text { slab with }=6.08 \mathrm{m} / \mathrm{s}^{2}

\text { Frictional force on 40 kg slab by 10 kg block, normal reaction \times \mu_{kinetic } }

Frictional force on 40 kg slab by 10 kg block = 98 × 0.4  

Frictional force on 40 kg slab by 10 kg block = 39.2 N  

40 \mathrm{kg} \text { slab will move with } \frac{\text { frictional force }}{\text { mass }}

40 \mathrm{kg} \text { slab will move with }=\frac{39.2}{40}

40 kg slab will move with = 0.98 \mathrm{m} / \mathrm{s}^{2}

\text { The "resulting action" on the slab is } 0.98 \mathrm{m} / \mathrm{s}^{2}

3 0
2 years ago
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