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statuscvo [17]
3 years ago
15

Liquid nitrogen boils at –195.8°C. Express the boiling point of liquid nitrogen in kelvin

Chemistry
1 answer:
inessss [21]3 years ago
4 0

Answer:

\boxed {\boxed {\sf 77.35 \ K}}

Explanation:

The Celsius and Kelvin scales are used to measure the temperature of matter.  Their scales and unit differences are the same (1 K increase = 1 °C increase), but they have different starting points.

So, the conversion is quite simple and only requires addition because of the different starting points. The formula is:

T_K = T_C+ 273.15

The boiling point of liquid nitrogen is -195.8 °C. We can substitute this value into the formula.

T_K= -195.8 + 273.15

T_K= 77.35 K

The boiling point of liquid nitrogen is 77.35 Kelvin.

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Beverly and Carl are in a race. Their graphs show the data.
Nikitich [7]

Given the data, the correct statement is

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

<h3>What is acceleration? </h3>

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

<h3>How to determine the initial acceleration of Beverly</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 15 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (15 – 0) / 10

a₁ = 1.5 m/s²

<h3>How to determine the final acceleration of Beverly</h3>
  • Initial velocity (u) = 15 m/s
  • Final velocity (v) = 35 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (35 – 15) / 40

a₂ = 0.5 m/s²

<h3>How to determine the initial acceleration of Carl</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 10 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (10 – 0) / 10

a₁ = 1 m/s²

<h3>How to determine the final acceleration of Carl</h3>
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 30 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (30 – 10) / 40

a₂ = 0.5 m/s²

SUMMARY

  • Initial acceleration of Beverly = 1.5 m/s²
  • Final acceleration of Beverly = 0.5 m/s²
  • Initial acceleration of Carl = 1 m/s²
  • Final acceleration of Carl = 0.5 m/s²

From the above calculations, we can see that Beverly's initial acceleration is higher than that of Carl's and their final acceleration is the same.

Therefore, the correct answer to the question is:

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

Complete question

See attached photo

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

8 0
2 years ago
Give the ground-state electron configuration for each of the following elements. After each atom is its atomic number in parenth
Anni [7]

Answer:

(a) ₁₉K: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

(b) ₁₀Ne: 1s² 2s² 2p⁶

---

(a) 3

(b) 6

(c) 7

Explanation:

We can state the ground-state electron configuration for each element following Aufbau's principle.

(a) ₁₉K: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

(b) ₁₀Ne: 1s² 2s² 2p⁶

Second part

(a) Al belongs to Group 13 in the Periodic Table. It has 13-10=3 electrons in the valence shell.

(b) O belongs to Group 16 in the Periodic Table. It has 16-10=6 electrons in the valence shell.

(c) F belongs to Group 17 in the Periodic Table. It has 17-10=7 electrons in the valence shell.

3 0
3 years ago
1.00 mole of an ideal gas at STP is cooled to -41°C while the
qwelly [4]

Answer:

V₂ = 18.13 L

Explanation:

Given data:

Mole of gas = 1 mol

Initial temperature = 273 K

Initial pressure = 1 atm

Final volume = ?

Final temperature = -41°C (-41+273 = 232 K)

Final pressure = 805 mmHg (805/760 = 1.05 atm)

Solution:

First of all we will calculate the initial volume of gas.

PV = nRT

V = nRT/P

V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm

V = 22.4 L/atm / 1 atm

V = 22.4 L     ( initial volume)

Now we will determine the final volume by using equation,

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 22.4 L ×  232 K / 273 K × 1.05 atm

V₂ = 5196.8 atm .L. K / 286.65 atm.K

V₂ = 18.13 L

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3 years ago
If the original 1 mL sample were dialyzed twice, successively, against 200 mL of the same HEPES buffer with 0 mM NaCl , what wou
Likurg_2 [28]
Sorry I am only in middle school
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3 years ago
Ben Tooclose is being chased through the woods by a bull moose which he attempting to photograph.the enormous mass of the bull m
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3 years ago
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