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statuscvo [17]
3 years ago
15

Liquid nitrogen boils at –195.8°C. Express the boiling point of liquid nitrogen in kelvin

Chemistry
1 answer:
inessss [21]3 years ago
4 0

Answer:

\boxed {\boxed {\sf 77.35 \ K}}

Explanation:

The Celsius and Kelvin scales are used to measure the temperature of matter.  Their scales and unit differences are the same (1 K increase = 1 °C increase), but they have different starting points.

So, the conversion is quite simple and only requires addition because of the different starting points. The formula is:

T_K = T_C+ 273.15

The boiling point of liquid nitrogen is -195.8 °C. We can substitute this value into the formula.

T_K= -195.8 + 273.15

T_K= 77.35 K

The boiling point of liquid nitrogen is 77.35 Kelvin.

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Answer:

condensation - B, melting - C, sublimation - A, freezing - D

Explanation:

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melting : melting  is process of change of phase of a substance from solid to liquid.

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Identify the nuclide that would be formed from the alpha particle emission of Fm-257.
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Answer: 1) The nuclide formed from the alpha decay of _{100}^{257}\textrm{Fm} is _{98}^{253}\textrm{Cf}

2) The nuclide formed from the beta-minus decay of _{98}^{253}\textrm{Cf} is _{99}^{253}\textrm{Es}

Explanation:

1) For alpha-decay

In this process, alpha particle is released.

Equation follows:

_{100}^{257}\textrm{Fm}\rightarrow _{98}^{253}\textrm{Cf}+_2^4\alpha

The nuclide formed is _{98}^{253}\textrm{Cf}

2) For beta-minus decay

In this process, a neutron is converted into a proton and an electron.

Equation follows:

_{98}^{253}\textrm{Cf}\rightarrow _{99}^{253}\textrm{Es}+_{-1}^0\beta

The nuclide formed is _{99}^{253}\textrm{Es}

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