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Airida [17]
3 years ago
14

Sorry the last one wasn’t 99 points but this one is 14 points sorry! But 14 points is a lot right? so please be prepared! Hshsuu

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Chemistry
2 answers:
vaieri [72.5K]3 years ago
5 0

Answer:

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jenyasd209 [6]3 years ago
3 0
Wrzcncxmmadhdshkkfdyopgfogdfujgfudswsggubxrinkvfususesgyefkonxqwyousgisdjlknxzvnmvssiiwtossgukilpojhfsdvgffffffcnkajsbd acavscgdbdbdhudjrbdvshdndjdvgyhhhdbsjzisjqbaodjfvtvsjsnsjspsjdvrvehsuwkoendodjt bsbdbdhdhdhdhrnfndjgwhdbdhejebrudhbdhdudehdhdvdnixydbdndkdibdnmsko
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Why is NaHCO3 a base?
worty [1.4K]

NaHCO3 is a product of a strong base and a weak acid reaction. Thus it has weak basic properties.

HCO3- ion is actually amphoteric, which means it can act as a base or an acid. But it is weaker than a strong acid or a strong base.

<span>HCO3- is amphoteric meaning it acts both as a B.L. Acid and a B.L. Base.. which is why it's used to neutralize both acid and base spills in the lab.</span>

7 0
3 years ago
What happens in nuclear fusion?
vfiekz [6]
The answer is B particles combine into a large amount of engery.
5 0
3 years ago
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Which phase is heat energy being released?
scZoUnD [109]

The answer is B
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6 0
3 years ago
C10H12O4S(s) + O2(g)  CO2(g) + SO2(g) + H2O(g)
ale4655 [162]

Answer: The coefficient for O_2(g) is 12.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

C_{10}H_{12}O_4S(s)+12O_2(g)\rightarrow 10CO_2(g)+SO_2(g)+6H_2O

Thus in the reactants, there are 12 molecules of oxygen in balanced chemical equation. Thus the coefficient for O_2(g) is 12.

8 0
2 years ago
What is the ∆G for the following reaction between O3 and O2? 3O2(g) 2O3(g) Given: O3: ∆H = 285.4 kJ ∆S = -137.14 J/K)
Natali [406]
We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)

I’m going to assume 0 degrees Celsius.
At 0 C (273 K):

dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ

The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.

This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
6 0
3 years ago
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