Your answer is the element of S I think.
Answer:
p orbital.
Explanation:
Valence electrons are the electrons in an atom holding the very last orbital which is used in chemical bonding with other elements. Their existence could define the chemical properties of that atom.
During the first energy in ionization of an N2 molecule the molecular orbital from which the electron could be extracted is the only one with the highest energy level. Nitrogen has its outermost orbital (p) containing three valence electrons. Each orbital is only half filled, and thus it is unstable Thus, the electron mission must have been removed from p orbital.
11 electrons , 11 protons , 12 neutrons.
Answer:
not 100% sure but I think it's unbalanced chemical
The phase's composition is as follows: 27
What is the alloy's composition?
Both have mass fractions of w a = w b = 0.5.
A-B alloy composition; C o = 57 wt% B - 43 wt% A
C b = 87 wt% B - 13 wt% A is the new phase composition.
Using the Lever rule, we can calculate the mole fraction (x i) or mass fraction (w i) of each phase of a binary equilibrium phase as follows:
W a = W b = 0.5
This provides us with;
0.5 = (C b - C o)/(C b - C a)
(87 - 57)/(87 - C a) = 0.5
30/0.5 = 87 - C a
60 = 87 - C a
C a = 87 - 60
C a = 27
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