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guapka [62]
3 years ago
11

2.1 km =

Mathematics
1 answer:
likoan [24]3 years ago
3 0
2,100,000 Centimeters
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On the school playground, the slide is due west of the tire swing and due south of the monkey bars. If the distance between the
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Answer:

Step-by-step explanation:

Draw a picture!

You get a right triangle with hypotenuse = 20 ft and horizontal leg = 12 ft

Use the Pythagorean Theorem to find the length of the vertical leg:

vertical leg = √(20²-12²) = √256 = 16 ft

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Part D
Alekssandra [29.7K]

The shrink or stretch of the image of PQRS which is the dilation of PQRS is given as follows;

  • The rule of the dilation is \underline{D_{\frac{1}{2} }}, followed by a reflection across the x-axis

Reason:

The given completed  table is presented as follows;

\begin{array}{|cc|c|} \mathbf{Original \ Coordinates}&&\mathbf{New \ Coordinates}\\(x, \ y)&&(,)\\K(3, \, 2)&&P(6, \, -4)\\L(1, \, 1)&&Q(2, \, -2)\\M(1, \, 3)&&R(2, \, -6)\\N(3, \, 3)&&S(6, \, -6)\end{array}

Length of the side \overline{LM} = 3 - 1 = 2

Length of the side \overline{MN} = 3 - 1 = 2

Length of the side \overline{NK} = 3 - 2 = 1

Length of the side \overline{LK} = \sqrt{(2 - 1)^2 + (3 - 1)^2} = \sqrt{5}

Length of the side \overline{RQ} = -2 - (-6) = 4

Length of the side \overline{RS} = 6 - 2 = 4

Length of the side \overline{SP} = -4 - (-6) = 2

Length of the side \overline{QP} = \sqrt{(6 - 2)^2 + (-4 - (-2))^2} = 2\cdot \sqrt{5}

\dfrac{\overline{LM}}{\overline{RQ}} = \dfrac{\overline{MN}}{\overline{RS}} = \dfrac{\overline{NK}}{\overline{SP}} = \dfrac{\overline{LK}}{\overline{QP}} = \dfrac{1}{2}

However, the coordinates of the image of PQRS, which is P'Q'R'S', following a dilation are'

P' \left(\dfrac{1}{2} \times 6, \, \dfrac{1}{2} \times (-4) \right) = P'(3, \, -2)

Q' \left(\dfrac{1}{2} \times 2, \, \dfrac{1}{2} \times (-2) \right) = Q'(1, \, -1)

R' \left(\dfrac{1}{2} \times 2, \, \dfrac{1}{2} \times (-6) \right) = R'(1, \, -3)

S' \left(\dfrac{1}{2} \times 6, \, \dfrac{1}{2} \times (-6) \right) = S'(3, \, -3)  

The transformation of the coordinates of P'Q'R'S', to KLMN are;

  • (x, y) → (x, -y)

which is equivalent to a reflection across the x-axis

Therefore, the transformation that gives the coordinate of KLMN from PQRS is a dilation by a scale factor of \underline{\dfrac{1}{2}}, which is a rule of dilation of \underline{D_{\frac{1}{2} }}, followed by a reflection across the x-axis

Learn more here:

brainly.com/question/12382913

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