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finlep [7]
3 years ago
12

Find the measure of

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

of what?

Step-by-step explanation:

if you could send a picture Thad be great

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In winter, the price of apples suddenly went up by$0.75 per pound. Sam bought 3 pounds of apples at the new price for a total of
White raven [17]

From the information given, the original price per pound was increased by $ 0.75
Let the original price be x, so the new price is x + 0.75

Sam bought 3 pounds of apples at new price and it cost him 5.88

so we form an equation:

3 (x + 0.75) = 5.88

3x + 2.25 = 5.88

3x = 5.88 - 2.25

3x = 3.63

x = 3.63 / 3

x = 1.21

Therefore the original price per pound is 1.21 dollars


4 0
3 years ago
Read 2 more answers
It was 38 kilometers from the encampment to the castle. Milton galloped to the castle and cantered back. If the round trip took
mario62 [17]
1) yes
2) no
3) a. yes
b. no
3) you have two question #3's...
4) Do your own homework
6 0
3 years ago
PLEASE HELP GIVING BRAINLIEST
Alexeev081 [22]

Answer:

(-5-3/2,3+1/2)

(-13/2,7/2)

option A is correct

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Read 2 more answers
Mr. F is buying 8 computers for the computer lab. if one computer costs $1,156, How much will the computers cost in all?
Andreas93 [3]

answer: $9248


explanation:

well, we know the cost for one, so if each computer costs the same, multiply the cost of one of them by 8 to get the total.

8 x 1,156 = 9248.

so, we can assume this is what the computers will cost in total because there seems to be no added tax or fees.


<em>i hope this helps, and have a great day! don't hesitate to ask if you need more help with this specific question! ♥ - eviezoom </em>


3 0
3 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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