Here when an object is placed on the level floor then in that case there are two forces on the object
1). Weight of object downwards (mg)
2). Normal force due to floor which will counterbalance the weight (N)
so when no force is applied on the box at that time normal force is counter balanced by weight.
Now here it is given that A person tried to lift the box upwards
So now there are two forces on the box
1). Applied force of person
2). Normal force due to ground
So now these two forces will counter balance the weight of the crate
So we can write an equation for force balance like
![F_g = F_n + F_a](https://tex.z-dn.net/?f=F_g%20%3D%20F_n%20%2B%20F_a)
given that
![F_g = mg](https://tex.z-dn.net/?f=F_g%20%3D%20mg)
here
m = 30 kg and
g = acceleration due to gravity = 10 m/s^2
![F_n = 150 N](https://tex.z-dn.net/?f=F_n%20%3D%20150%20N)
now from above equation
![30*10 = 150 + F_a](https://tex.z-dn.net/?f=30%2A10%20%3D%20150%20%2B%20F_a)
![F_a = 300 - 150 = 150 N](https://tex.z-dn.net/?f=F_a%20%3D%20300%20-%20150%20%3D%20150%20N)
So force applied by the person must be 150 N
I think it is high pressure / gravity and high temperatures
Answer:
Check attachment for better understanding
Explanation:
Given that,
Current in wire I =2.2A
Capacitor plate dimension is 2cm by 2cm
s=2cm=2/100 = 0.02m
Rate at which electric field Is changing dE/dt?
The current in the wires must also be the displacement current in the capacitor. We find the rate at which the electric field is changing from
ID = ε0•A•dE/dt
Where ε0 is a constant
ε0= 8.85×10^-12C²/Nm²
Area of the square plate is
A =s² =0.02² = 0.0004m²
Then,
Make dE/dt the subject of formula
dE/dt = ID/ε0A
dE/dt = 2.2 / (8.85×10^-12 ×4×10^-4)
dE/dt = 6.215×10^14 V/m-s
Or
dE/dt = 6.215×10^14 N/C.s
The rate at which the electric field is changing between the plates is 6.215×10^14 N/C.s
Answer:
Explanation:
With the help of expression of time period of pendulum we can calculate the height of the branch . The swinging tire can be considered equivalent to swinging bob of a pendulum . Here length of pendulum will be equal to height of branch .
Let it be h . Let the time period of swing of tire be T then from the formula of time period of pendulum
where l is length of pendulum .
here l = h so
![h = \frac{T^2g}{4\pi^2}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7BT%5E2g%7D%7B4%5Cpi%5E2%7D)
If we calculate the time period of swing of tire , we can calculate the height of branch .
The time period of swing of tire can be estimated with the help of a stop watch . Time period is time that the tire will take in going from one extreme point to the other end and then coming back . We can easily estimate it with the help of stop watch .
i believe it is density but i'm not for certain try looking it up somewhere else