For the part a) we need only the momentum of the box and we have the data to find it.
Momentum is given by,

where clearly, p is the momentum, m the mass of the box and v is the velocity.
Substituting,

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,
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<em>It is the same that part a)</em>
The actual answer is 7/100
1)
first you find the maxium force that the car can produce.
f=ma
Fmax=(1100kg)(6m/s^2)
then use f = ma again to find the accel with the passengers
Fmax=(1100kg +1650kg)(a)
=> a = (1100kg)(6m/s^2)/( 1100kg +1650kg)
= 2.4 m/s^2
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D)
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