<span>0.298 M
The balanced equation for the reaction is
HCl + NaOH = H2O + NaCl
So for every mole of NaOH used, one mole of HCl is neutralized. So let's determine how many moles of NaOH we used. That will simply be the volume (in liters) of solution multiplied by the molarity. So
0.0493 L * 0.151 mol/L = 0.0074443 mol
Because of that 1:1 ratio, we now know that 0.0074443 moles of HCl was in the sample. Since molarity is moles per liter, a little division will give us the molarity of the HCl solution. So
0.0074443 mol / 0.025 L = 0.297772 mol/M = 0.297772 M
Rounding to 3 significant figures gives 0.298 M.</span>
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Answer:
im 99% sure it's 175.
Explanation:
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Answer:
Explanation:
Ok, so I suppose you meant NaCl. But ok:
So we have the formula moles = grams/MM, where MM is molar mass. The molar mass of NaCl is 58.44 g/mol. That means that 55/58.44 is the number of moles which appears to be 0.94 moles.
