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3 years ago

If the reactants on the left side of a chemical equation are C3H8 + 5O2, the products in a balanced equation could be

Chemistry

2 answers:

devlian [24]3 years ago

8 0

Answer: $3CO_2+4H_2O$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.

The balanced chemical reaction will be:

$C_3H_8+5O_2 \rightarrow 3CO_2+4H_2O$

Basile [38]3 years ago

6 0

Holy I'm not that smart lol but I'll get back to you

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Consider the five balanced chemical reactions listed below, all using O2 as a reactant. Normally, O2 is an excess reagent for re

ad-work [718]

Answer: option E. None because in all the reactions O2 is in excess

Explanation:

7 0

3 years ago

[OH-] for a solution is

solong [7]

Answer:

B = basic

Explanation:

Given data:

[OH⁻] = 5.35×10⁻⁴M

pH = ?

Solution:

pOH = -log[OH⁻]

pOH = - [5.35×10⁻⁴]

pOH = 3.272

it is known that,

pH + pOH = 14

pH = 14- pOH

pH = 14 - 3.272

pH = 10.728

The acidic pH is range from zero to less than 7 while 7 pH is neutral and above 7 the pH is basic. So, the given solution is basic.

8 0

3 years ago

Read 2 more answers

What decomposers are in a estuary ?

belka [17]

They are Common Soil Bacteria Nematodes.

Hope this helps:)

7 0

4 years ago

HELP PLEASE!! ASAP What would the mass be in kg?

fgiga [73]

Answer:

i guess answer is 0.0600

Explanation:

Here,

Density=0.791g/cm^3

Volume=75.89ml

So,

Mass=Density*Volume

=0.791g/cm^3×75.89ml

=60.02g/cm^3.ml

Expressing them in kg

60.02/1000

=0.0600 kg

4 0

3 years ago

Which types of electron orbitals will have higher energy than a 4d orbital?

alexdok [17]

Answer:

D) 4f

Explanation:

To determine which electron orbital that will have higher energy than a 4d orbital, we write the electron configuration starting with s-orbital.

2s 2p

3s 3p 3d 3f

4s 4p 4d 4f

5s 5p 5d 5f

6s 6p 6d 6f

7s 7p 7d 7f

In ascending order, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 3f, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

From the electronic configuration formula above, the electron orbitals that have higher energy than a 4d orbital are 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

Therefore, 4f is the correct answer.

8 0

3 years ago