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3 years ago

If the reactants on the left side of a chemical equation are C3H8 + 5O2, the products in a balanced equation could be

Chemistry

2 answers:

devlian [24]3 years ago

8 0

Answer: $3CO_2+4H_2O$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.

The balanced chemical reaction will be:

$C_3H_8+5O_2 \rightarrow 3CO_2+4H_2O$

Basile [38]3 years ago

6 0

Holy I'm not that smart lol but I'll get back to you

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A student reports the following measurements for a set of pennies: 102.0mL, 91.0 g. What is the density of the pennies.

zysi [14]

Answer:

V = 102.0 ml

m = 91.0 ml

density = ...?

density = m / V

= 91.0 / 102.0

= 0.89215 g/ml

7 0

3 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

A common reaction is the formation of butyric acid from butyl alcohol. butyric acid is what causes the odor of rancid butter. ba

Nastasia [14]

Butyl Alcohol on reaction with Oxygen produces Butyric Acid and Water.

The Balance Chemical equation is as follow,

C₄H₉OH + O₂ → C₄H₇O₂H + H₂O

Result:
The equation given in statement is already balanced.

6 0

3 years ago

Read 2 more answers

A community consists of all the organisms in an ecosystem that belong to the same species.

choli [55]

Answer:

False

Explanation:

A community consists of all the organisms in an ecosystem that belong to the same species. Population density occurs when two or more organisms seek the same resource at the same time. A carrying capacity is anything that restricts the number of individuals in a population.

3 0

2 years ago

Read 2 more answers

If the half-life of a radioisotope is 10,000 years, the amount remaining after 20,000 years is

Cloud [144]

Answer:

Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.

Explanation:

The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:

Time_________________ Amount

t=0_____________________x

t=10,000 years____________x/2

t=20,000 years___________x/4

During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.

6 0

3 years ago