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3 years ago

Compare the dermis and epidermis. Explain the function of each.

Chemistry

1 answer:

lianna [129]3 years ago

5 0

Answer:

The epidermis, the outermost layer of skin, provides a waterproof barrier and creates our skin tone. The dermis, beneath the epidermis, contains tough connective tissue, hair follicles, and sweat glands.

Explanation:

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4.65 L of nitrogen at standard pressure is compressed into a 0.480 L container. What is the new pressure in kPa?

Semenov [28]

Assuming that nitrogen gas is ideal, we can use the equation PV = nRT to relate first conditions to the second condition. At constant temperature, pressure and volume are indirectly related as follows:

P = k / V

k is equal nRT

P1V1 = P2V2
P2 = 101.325 ( 4.65 ) / .480 = 981.586 kPa

6 0

3 years ago

A 100.0 mL sample of 0.300 M NaOH is mixed with a 100.0 mL sample of 0.300 M HNO 3 in a coffee cup calorimeter. If both solution

uysha [10]

Answer:

THE STANDARD HEAT OF NEUTRALIZATION OF THE BASE SODIUM HYDROXIDE BY THE ACID HYDROGEN TRIOXONITRATE V ACID IS -56 kJ / mol.

Explanation:

Volume of 0.3 M NaOh = 100 mL

Volume of 0.3 M HNO3 = 100 mL

Initail temp of NaOH and HNO3 = 35 °C = 35 + 273 K = 308 K

Final temp. of mixture = 37 °C = 37 + 273 K = 310 K

We can make the following assumptions form the question given:

1. specific heat of the reaction mixture is the same as the specific heat of water = 4.2 J/g K

2. the toal mass of the reaction mixture is 200 mL = 200 g since no heat is lost to the calorimeter or surrounding.

3. initail temperature of the reaction mixture is equal to the average temperature of the two reactant solutions

= ( 308 + 308 /2) = 308 K

4. Rise in temeperature for the reaction = 310 -308 K = 2 K

Then the total heat evolved during the reaction = mass * specifc heat capacity * temperature change

Heat = 200 g * 4.2 J/g K * 2 K

Heat = 1680 J

EQUATION FOR THE REACTION

HNO3 + NaOH -------> NaNO3 + H20

From the equation, 1 mole of HNO3 reacts with 1 mole of NaOH to prouce mole of water.

100 mL of 0.5 M HNO3 contains 100 * 0.3 /1000 = 0.03 mole of acid

This result is same for the base NaOH = 0.03 mole of base

So therefore,

0.03 mole of acid will react with 0.03 mole of base to produce 0.03 mole of water to evolved 1680 J of heat energy.

The production of 1 mole of water will evolve 1680 / 0.03 J of heat

= 56 000 J or 56 kJ of heat energy per mole of water.

So therefore, 1the standard heat of neutralization of sodium hydroxide by trioxoxnitrate V acid is -56 kJ/mol.

5 0

3 years ago

Draw the structures of organic compounds a and b omit all by products thf

Brums [2.3K]

The reaction is shown below,

Step 1: Hydration of Alkene:
In first step Ethene is hydrated to Ethanol through Hydroboration Reaction.

Step 2: Oxidation of Primary Alcohol:
In this step partial oxidation of ethanol is carried out using mild Oxidizing agent <span>Pyridinium chlorochromate (PCC) and Acetaldehyde is produced.

Step 3: Reduction of Acetaldehyde followed by Oxidation:
In this step, first acetaldehyde is reduced to secondary alcohol using grignard reagent. After that the sec. alcohol is oxidized to ketone by using oxidizing agent CrO</span>₃.

6 0

3 years ago

Calculate the vapor pressure at 25° C of a

Leokris [45]

Answer: 35.4 degrees

Explanation: because it cold

7 0

4 years ago

Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying

PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? ( $K_a$ for HF is $6.8\times 10^{-4}$ .)