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MissTica
3 years ago
14

The moon rises and sets every day, like the sun. Sarah noticed that the moon was sometimes visible at night and sometimes during

the day. She noted when she FIRST saw the moon (moon-rise) on two days in April. She looked up the time in the newspaper for moon-set. Both were different. Why? A) The moon is orbiting the Earth once per month. B) The night sky is moving east to west over Earth. C) The Earth is moving in an opposite direction from the moon. D) The apparent change in position is related to the Sun's reflection.
Chemistry
1 answer:
eimsori [14]3 years ago
3 0

the answer is A.) the moon is orbiting the earth once per month

its the only logical answer, the others are either impossible or illogical

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It seems like the answer is C, you really just need to use the process of elimination.

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4 years ago
The ksp of pbi2 is 1.4 x 10-8. what is the molar solubility of lead(ii iodide in a solution of 0.400 m sodium iodide?
tino4ka555 [31]
The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:

PbI2 = Pb^2+ + 2I-

We solve as follows:

Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
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3 years ago
The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
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Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

So, the amount of dihydrogen produced = 0.078 \frac{kg}{s}

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Answer:

I think it's C sorry if I am wrong

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