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gizmo_the_mogwai [7]
3 years ago
6

How many joules of heat are lost by 1000g of granite as it cools from 41.2 Celsius to -12.9 Celsius?

Chemistry
1 answer:
lilavasa [31]3 years ago
8 0

Answer: The amount of heat released is 42739 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat released =?

c = heat capacity of granite = 0.790J/g^0C

Initial temperature  = T_i = 41.2^0C

Final temperature of the calorimeter  = T_f  = -12.9^0C

Change in temperature ,\Delta T=T_f-T_i=(-12.9-41.2)^0C=-54.1^0C

Putting in the values, we get:

Q=1000g\times 0.790J/g^0C\times -54.1^0C=-42739J

As heat comes out to be negative, that means the heat has been released and the amount of heat released is 42739 Joules

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