Question

How many joules of heat are lost by 1000g of granite as it cools from 41.2 Celsius to -12.9 Celsius?

Answer 1

Answer: The amount of heat released is 42739 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat released =?

c = heat capacity of granite = $0.790J/g^0C$

Initial temperature  = $T_i$ = $41.2^0C$

Final temperature of the calorimeter  = $T_f$  = $-12.9^0C$

Change in temperature ,$\Delta T=T_f-T_i=(-12.9-41.2)^0C=-54.1^0C$

Putting in the values, we get:

$Q=1000g\times 0.790J/g^0C\times -54.1^0C=-42739J$

As heat comes out to be negative, that means the heat has been released and the amount of heat released is 42739 Joules