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stich3 [128]
3 years ago
9

Nitrogen dioxide decomposes at 300°C via a second-order process to produce nitrogen monoxide and oxygen according to the followi

ng chemical equation.
2 NO2(g) → 2 NO(g) + O2(g).
A sample of NO2(g) is initially placed in a 2.50-L reaction vessel at 300°C. If the half-life and the rate constant at 300°C are 11 seconds and 0.54 M-1 s-1, respectively, how many moles of NO2 were in the original sample?

I just need an idea on how to approach this problem. ...?
Chemistry
1 answer:
qaws [65]3 years ago
4 0
This problem can be simplified by assuming that the reaction took place in a rigid vessel, that is, the volume is held constant. It is also safe to assume that the reaction is isothermal. The first step here is to derive an expression for the dependency of the reactant concentration with time. Since it is stated that the reaction is second order we start with

-dC/dt = k C^2

where

C is the amount of reactant (NO2)
t is time 
k is the reaction rate constant

The negative sign indicates that the concnetration is decreasing with time. Solving the equation, we get

1/Co - 1/C = kt

where Co is the initial amount of NO2

Now we are given the half life which is the time in which the amount of NO2 is halved, that is, C = 0.5Co. Therefore we can solve the initial amount of NO2 (Co) by substituting t = 11 s, k = 0.54 M-1s-1 and C = 0.5Co

Hope this helps
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Which reaction type is really part of another type of reaction but treated separately? Explain
Novosadov [1.4K]

Answer:

Oxidation - reduction reaction which is called redox reaction.

Explanation:

The type of reaction that is a part of another type but treated separately is called Oxidation - reduction reaction.

Thus is because they usually involve 2 separate half reactions which are oxidation reactions that involve loss of electrons and then reduction equations which involve gain of electrons.

They are treated separately for example when sodium reacts with chlorine to form sodium chloride.

2Na + Cl2 = 2NaCl

Now, sodium undergoes oxidation by loosing elctrons and it's half reaction is;

2Na → 2Na​^(+) + 2e^(-)

​​Meanwhile chlorine undergoes reduction by gaining electrons and its half reaction is;

Cl2 + 2e^(-) → 2Cl^(-)

6 0
3 years ago
When one form of energy is converted to another form in any physical or chemical change, energy input alwasy equals energy outpu
aliya0001 [1]
In the context of chemistry, yes. Energy input is always equal to the energy output.
5 0
3 years ago
In which circumstance is displacement the same as distance traveled?
Ede4ka [16]
Distance travelled will be equal to displacement when the line drawn is completely straight. 

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8 0
3 years ago
Read 2 more answers
Calculate the number of grams of carbon found in a 5 mole sample of carbon.
Ksenya-84 [330]

Answer:

60g

Explanation:

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3 0
3 years ago
A dehydration reaction starting with 3.8 g cyclohexanol produces 2.6 g cyclohexene. Calculate the theoretical yield for this rea
diamong [38]

Answer:

Theoretical yield of C6H10 = 3.2 g.

Explanation:

Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.

Equation of the reaction

C6H11OH --> C6H10 + H2O

Moles of C6H11OH:

Molar mass of C6H110H = (12*6) + (1*12) + 16

= 100 g/mol

Mass of C6H10 = 3.8 g

number of moles = mass/molar mass

=3.8/100

= 0.038 mol.

Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.

Therefore, 0.038 moles of C6H10 was produced.

Mass of C6H10 = molar mass * number of moles

Molar mass of C6H10 = (12*6) + (1*10)

= 82 g/mol.

Mass = 82 * 0.038

= 3.116 g of C6H10.

Theoretical yield of C6H10 = 3.2 g

4 0
3 years ago
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