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4 years ago

How much heat is absorbed by a 29g iron skillet when its temperature rises from 9oC to 105oC?

1 answer:

5 0

We have:

Mass (m) of the iron skillet = 29 grams
Difference in temperature (Δt) = 105 - 9 = 96°C
Heat capacity of iron = 0.449 J/g °C

The energy (Q) is given by:

Q = m × Δt × specific heat
Q = 29 grams × 96 °C × 0.449 J/g°C
Q = 1250.016 Joules

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Please help! This is due tomorrow and I absolutely need help.

zysi [14]

Answer:

Correct answer: 11. Total distance d = 200m ; 12. Vav = 3.63m/s ;

13. Total displacement Dt = 0m ; 14. V₂(10s-15s) = 0 m/s ;

15. V₃(15s-40s) = 4 m/s ; 16. V₁(0s-10s) = 6 m/s > V₄(40s-55s) = 2.67 m/s

Explanation:

The whole movement can be divided into four stages.

In the first stage the subject moves 60m in a positive direction for 10s,

in the other it is stationary for 5s, in the third it moves 100m in the opposite (negative) direction for 25s and in the fourth in the positive 40m for 15s.

11. Total distance = 60 + 0 + 100 + 40 = 200m

12. The formula for calculating the average speed (velocity) is

Vav = (S₁ + S₂ + S₃ + S₄) / (t₁ + t₂ + t₃ + t₄)

Vav = (60 + 0 + 100 + 40)/ (10 + 5 + 25 + 15) = 200/55 = 3.63 m/s

13. The movement started from the origin and ended at the origin

Total displacement is zero meters.

14. The speed between 10s and 15s is zero, because he did not move.

15. V₃ = S₃/t₃ = 100/25 = 4 m/s

16. V₁ = S₁/t₁ = 60/10 = 6 m/s and V₄ = S₄/t₄ = 40/15 = 2.67 m/s

V₁ > V₄

God is with you!!!

4 0

3 years ago

You are trying to decide between two new stereo amplifiers. One is rated at 130 W per channel and the other is rated at 200 W pe

NARA [144]

Answer:

The sound level will be 1.870 dB louder.

Explanation:

Given that,

Power = 130 W

Power = 200 W

We need to calculate the sound level

Using formula of sound level

$I_{dB}=10\log(\dfrac{I}{I_{0}})$

For one amplifier,

$I_{1}=10\log(\dfrac{130}{I_{0}})$ ...(I)

For other amplifier,

$I_{2}=10\log(\dfrac{200}{I_{0}})$ ...(II)

For difference in dB levels

$I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}})-10\log(\dfrac{130}{I_{0}})$

$I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}}\times\dfrac{I_{0}}{130})$

$I_{2}-I_{1}=10\log(\dfrac{200}{130})$

$I_{2}-I_{1}=1.870\ dB$

Hence, The sound level will be 1.870 dB louder.

7 0

3 years ago

Why are water storage tanks usually built on towers or hilltops??

Komok [63]

Because when you open the faucet, you want the water to
rush out with pressure, not just dribble or ooze out. The
water has to be supplied to the user with pressure. Either
you supply it from a height, or else you'll need to use pumps
to make the pressure.

8 0

3 years ago

Kiley went 5.7 km/h north and went 5.8km/h west. From start to finish,she went 8.1 km/h northwest which best describes her numbe

ladessa [460]

These values are all vectors since they all possess both magnitude and direction.

8 0

3 years ago

A firework is fired from the ground straight up on a planet with an acceleration due to gravity of 10.56 m/s/s. The firework wil

n200080 [17]

Answer:

h = 384.4 m

t = 8.5 s

Explanation:

The firework will explode at the highest point. Because it would start to move downward at the highest point. Using 3rd equation of motion:

2ah = Vf² - Vi²

where,

a = acceleration due to gravity at that planet = -10.56 m/s²

h = maximum height = ?

Vf = Final velocity = 0 m/s (since, firework stops at highest point)

Vi = Initial Velocity = 90.1 m/s

Therefore,

2(-10.56 m/s²)(h) = (0 m/s)² - (90.1 m/s)²

Now, we use 1st equation of motion:

Vf = Vi + at

0 m/s = 90.1 m/s + (-10.56 m/s²)(t)

3 0

3 years ago