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3 years ago

A glass falls from a table top and smashes on the floor 0.6 seconds later. How high is the table?

Physics

1 answer:

soldi70 [24.7K]3 years ago

5 0

Answer:

1.8 m

Explanation:

Given: Glass falls from a table, smashes 0.6 seconds later

To find: How high a table is

Formula: Vv=gt, dv=1/2gt^2, t=2d/g

Solution: A table's height is measured from the top of the edge down to the floor. The tables are shown both have a height of 30 inches, which is common for many tables.

Data

t = 0.6s

g = 9.81 m/s²

d = ?

Equation

d = $\frac{1}{2}$ $gt$ ²

Math & Units

d = 4.905 (0.6²)
d = 442.676

Hence the table is 1.8 m high

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geniusboy [140]

Answer:

Apply the following formulae horizontally And get A value for time

Remember horizontal acceleration is zero

$s = ut + \frac{1}{2}a {t}^{2} \\ 0.8 = 1.7 \times t \\ \frac{0.8}{1.7} = t \\ t = 0.47s$

and then to find the height apply the same above equation vertically...remember vertical initial velocity is zero

$s = ut + \frac{1}{2} a {t}^{2} \\ s = \frac{1}{2} \times 10 \times (0.47) ^{2} \\ s = 1.1045m$

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3 years ago

Match: Substance ....... Definition Lewis base A. Provides H in water Bronsted-Lowry base B. Provides OH - in water Arrhenius ac

algol13

Answer:

A. Provides H in water - Arrhenius acid

B. Provides OH - in water - Arrhenius base

C. Proton donor - Bronsted-Lowry acid

D. Proton acceptor - Bronsted-Lowry base

E. Electron pair donor - Lewis base

F. Electron pair acceptor - Lewis acid.

Explanation:

Definition:

A Lewis base is any substance, such as the OH- ion, that can donate a pair of nonbonding electrons. A Lewis base is therefore an electron-pair donor.

A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction. Also, a Bronsted-Lowry base accepts hydrogen ions.

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4 years ago

A car starts from rest, speeds up with constant acceleration, and travels 400 meters in 10 seconds. What was the acceleration of

PIT_PIT [208]

Answer:

Acceleration of the car will be $a=8m/sec^2$

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that $s=ut+\frac{1}{2}at^2$

So $400=0\times 10+\frac{1}{2}\times a\times 10^2$

$a=8m/sec^2$

So acceleration of the car will be $a=8m/sec^2$

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3 years ago

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Answer:PV=nRT

Ideal gas equation

Explanation:

PV=nRT

Ideal gas equation

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Hope this helps!

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