Change in velocity per time
Answer:
a) correct answer is C
, b) 14º from the west to the north, c) v_{1g} = 300.79 km / h
Explanation:
This is a relative speed exercise using the addition of speeds.
1) when it is not specified regarding what is being measured, the medicine is carried out with respect to the Z Earth, therefore the correct answer is C
2 and 3) In this case we must compose the speed using the Pythagorean Theorem.
² =
² +
²
where v_{1a} is the speed of the airplane with respect to the air, v_{1g} airplane speed with respect to the Earth, v_{ag} air speed with respect to the Earth
in this case let's clear the speed of the airplane with respect to the Earth
v_{1g} = √(v_{1a}² - v_{ag}²)
v_{1g} = √ (310² - 75²)
v_{1g} = 300.79 km / h
we find the direction of the airplane using trigonometry
sin θ = v_{ag} / v_{1a}
θ = sin⁻¹ (v_{ag} /v_{1a})
θ = sin⁻¹ (75/310)
θ= 14º
the pilot must direct the aircraft at an angle of 14º from the west to the north
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Answer:
Check the explanation
Explanation:
A) 7th Harmonic. (Of an open ended pipe, odd harmonics are allowed (3rd overtone))
b) f = n v / 4 L
n = 7
f = 7 x 350 / 4 x 0.41 = 1493.9 Hz
c) Let level of water H, If reduces the effective length of pipe
Using, f = n v / 4 Leff
n = 1
251.8 = 1 x 350 / 4 ( 0.41 - H)
H = 0.0625m
H = 6.25 cm