Answer:
Mass of water,
Explanation:
Given that,
Surface area of the reservoir, A = 30 km² = 3 × 10⁷ m²
Average depth, d = 49 m
The volume of the reservoir is V such that,
We have to find the mass of water is held behind the dam. It can be calculated using the expression for density. We know that density of water, d = 1000 kg/m³
Density,
Hence, this is the required solution.
Explanation:
Degausser is a device used by automatically manipulating the alignment of magnetic domains on the medium to avoid data stored on computer and laptop hard disks, floppy disks, and magnetic cassette. There was a mistake. Therefore, a degausser is used to remove all audio, video and data signals from magnetic store media completely.
We use a fundamental kinematic equation as follows:
V = Vo + g*t.
<span>Tr = (V-Vo)/g = (0-10)/-10 = 1 s. = </span><span>time to reach max. height </span>
<span>Tf = Tr = 1 s. = Fall time or time to fall back to edge of bldg. </span>
<span>3-Tr-Tf = 3-1-1 = 1 s. Below edge of bldg. </span>
<span>d = Vo*t + 0.5g*t^2. </span>
<span>d = 10*1 + 5*1^2 = 15 m. <---- OPTION C</span>
Answer:
16 ohms
Explanation:
V=
I
⋅
R
where, V is the net potential difference in the circuit, I is the current in the circuit and R is the net resistance of the circuit.
In this case, V
=
240 volts, I
=
15 amperes.
240
=
15
⋅
R
⇒
R
=
240/
15
=
16 ohms
Answer:
-14.2m/s
Explanation:
Given parameters:
Initial velocity of the ball = 25m/s
Time = 4s
Unknown:
Final velocity of the ball = ?
Solution:
To solve this problem, we use the expression below;
v = u - gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 25 - (9.8 x 4) = -14.2m/s