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Inessa05 [86]
3 years ago
11

A

Physics
1 answer:
malfutka [58]3 years ago
4 0

Answer:

<em>The penny will hit the ground at 6.39 seconds</em>

Explanation:

<u>Free Fall</u>

The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:

\displaystyle y=\frac{gt^2}{2}

Where g=9.8\ m/s^2, and t is the time.

Solving for t:

\displaystyle t=\sqrt{\frac{2y}{g}}

Using the value y=200:

\displaystyle t=\sqrt{\frac{2*200}{9.8}}

t=6.39 sec

The penny will hit the ground at 6.39 seconds

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Crops drain the soil of nutrients

Explanation:

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What two simple machines make up an axe?
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The distance from the Moon to Earth is 3.9 x 10^8 meters. What is the time required for a light ray to travel from the Moon to E
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2 years ago
During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxima
vova2212 [387]

Answer:

The value  F  =  0.1396 \ N

Explanation:

From the question we are told that

   The volume blood  ejected is  V  =  65 \ cm^3  = 65*10^{-6} \  m^3

    The velocity of the blood ejected is  v  = 103 \  cm/s  = \frac{103}{100} = 1.03 \ m/s

    The density of blood is  \rho = 1060 \  kg/m^3

     The heart beat is R = 59 \  bpm(beats \  per \  minute) = \frac{59}{60}= 0.9833\ bps

The average force exerted by the blood on the wall of the aorta is mathematically represented as

      F  =  2 * \rho  *  V  *  R *  v

=>    F  =  2 * 1060  *  65*10^{-6}  *  0.9833 *  1.03

=>    F  =  0.1396 \ N

8 0
3 years ago
A capacitor is connected across an ac source. Suppose the frequency of the source is doubled. What happens to the capacitive rea
fgiga [73]

The capacitive reactance is reduced by a factor of 2.

<h3>Calculation:</h3>

We know the capacitive reactance is given as,

Xc = \frac{1}{2\pi fC}

where,

Xc\\ = capacitive reactance

f = frequency

C = capacitance

It is given that frequency is doubled, i.e.,

f' = 2f

To find,

Xc =?

Xc' = \frac{1}{2\pi f'C}

      = \frac{1}{2\pi 2f C}

      = \frac{1}{2} (\frac{1}{2\pi fC} )\\

Xc' = \frac{1}{2} Xc

Therefore, the capacitive reactance is reduced by a factor of 2.

I understand the question you are looking for is this:

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

  1. The capacitive reactance is doubled.
  2. The capacitive reactance is traduced by a factor of 4.
  3. The capacitive reactance remains constant.
  4. The capacitive reactance is quadrupled.
  5. The capacitive reactance is reduced by a factor of 2.

Learn more about capacitive reactance here:

brainly.com/question/23427243

#SPJ4

3 0
2 years ago
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