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elixir [45]
3 years ago
9

HELP HELP please. I’m failing i genuinely need help i’m begging you

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

Graph 1:

y-intercept =  7

Slope =  -1/2   <--- (It's a fraction) (-1 over 2)

Equation:  y = -1/2x + 7

________________________________

Graph 2:

y-intercept =  4

Slope =  5/6   <--- (It's a fraction) (5 over 6)

Equation:  y = 5/6x + 4

_________________________________

Graph 3:

y-intercept =  9

Slope =  -5/7   <--- (It's a fraction) (-5 over 7)

Equation:  y = -5/7x + 9

Hope this Helps  :)

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The given curve is rotated about the y-axis. find the area of the resulting surface. y = 1 3 x3/2, 5 ≤ x ≤ 12
Katyanochek1 [597]
The area of the resulting figure will be given by:
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Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

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With this equation, we can factor each equation:

\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}

We can cancel out like terms since they would be dividing each other:

\frac{x-4}{2x-2}

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Answer:

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Step-by-step explanation:

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