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3 years ago

Help please All the questions!

Mathematics

1 answer:

SashulF [63]3 years ago

6 0

Answer:

9. 32.

10. 6.

11. 10 to 15.

12. 32%

Step-by-step explanation:

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(x2 + 5x - 14) = (x - 2)

Sveta_85 [38]

Answer:

x = 2

x = -6

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3 years ago

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HELPPP PLSSS ITS DUE TOMORROW

Alinara [238K]

<h2>Answer :</h2>

We'll be using the Pythagoras property to solve this question.

According to the Pythagoras property,

H² = B² + P²

H denotes hypotenuse

B denotes base

P denotes perpendicular

Here,

H = x
P = 35 cm
B = 12 cm

→ (x)² = (35 cm)² + (12 cm)²

→ x² = 1225 cm² + 144 cm²

→ x² = 1369 cm²

→ x = √(1369 cm²)

→ x = 37 cm

Therefore, value of x is 37 cm. 

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3 years ago

Solve for x <img src="https://tex.z-dn.net/?f=%5Cbold%7Bx%20%7B%7D%5E%7B2%7D%20%2B%205x%20%2B%206%20%3D%200%7D" id="TexFormul

finlep [7]

Answer:

x = -2
x = -3

Step-by-step explanation:

$\bf {x}^{2} + 5x + 6 = 0$

Write the equation in factored form.

$\bf (x + 2)(x + 3) = 0$

Separate equations, and set each factor to zero.

$\bf x + 2 = 0$

$\bf x + 3 = 0$

Rearrange and isolate the variable to find the solutions

$\bf x = - 2$

$\bf x = - 3$

------------------------------------

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2 years ago

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A computer program has a bug that causes it to fail once in every thousand runs, on average. In an effort to find the bug, indep

Serhud [2]

Answer:

The standard deviation of the number of runs required is 2447.26

Step-by-step explanation:

For each run, there are only two possible outcomes. Either the program fails, or it does not. The probability of the computer failing during a run is independent of other runs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation for the expected number of trials for r sucesses is:

$\sqrt{V(X)} = \sqrt{\frac{r(1-p)}{p^{2}}}$

A computer program has a bug that causes it to fail once in every thousand runs, on average.

This means that $p = \frac{1}{1000} = 0.001$

In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?

This means that r = 6. So

$\sqrt{V(X)} = \sqrt{\frac{6*0.999}{(0.001)^{2}}} = 2447.26$

The standard deviation of the number of runs required is 2447.26

8 0

3 years ago

2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.

vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

$a_1 = 2.8$

$a_2 = 3.4$

Common difference = $a_2 - a_1 = 3.4 - 2.8 = 0.6$ .

Expression for the nth term:

$a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n$

n = 50 for the fiftieth term. Therefore

$a_{50} = 2.2 + 0.6 \times 50 = 32.2$ .

6 0

3 years ago