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jok3333 [9.3K]
3 years ago
10

3x+2y=6 and y=1/3x-11 perpendicular or parallel

Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.

For two lines  y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate  k1 and k2.

To calculate the slope k of any line, you have to change the equation to y=kx+b

For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))

For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)

Now you can get the answer: The two lines neither parallel nor perpendicular.

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Two equations are given below: a – 3b = 22 a = b – 2 What is the solution to the set of equations in the form (a, b)? (–10, –8)
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a - 3b = 22
a = b - 2

We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
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Now substitute -12 for b in a = b - 2
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Thus, the solution is a = -14 and b = -12

The correct option is the last one (-14,-12)


If you have questions about my answer, please let me know.


Good luck! 

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