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Veseljchak [2.6K]
2 years ago
9

Plzzzzzzzzzzzz help with escape room​

Mathematics
1 answer:
Olenka [21]2 years ago
8 0

Answer:

where is room bro I dont see

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What is the slope of a line that is perpendicular to the line whose equation is 3x+2y=6 3 x + 2 y = 6 ?
Tanzania [10]

Answer:

The slope of the line perpendicular to the given line is 2/3

Step-by-step explanation:

step 1

Find the slope of the given line

we have

3x+2y=6

isolate the variable y

2y=-3x+6

y=-(3/2)x+3

The slope of the given line is m=-(3/2)

step 2

Find the slope of the line perpendicular to the given line

Remember that

If two lines are perpendicular, their slopes are opposite reciprocal of each other ( the product of their slopes is equal to -1)

so

m1*m2=-1

we have

m1=-3/2

so

m2=2/3

therefore

The slope of the line perpendicular to the given line is 2/3

6 0
3 years ago
Help me ASAP! PLEASE
velikii [3]

Answer:

15

Step-by-step explanation:

Since the total degrees of ANY triangle is 180 degrees, start by subtracting 63 and 45 by 180.

180-63-45=72

Now take the 12 from (4x-12) and subtract that from 72.

72-12=60

Now divide 60 by 4 from the 4x.

60/4=15.

5 0
2 years ago
Please look at the screen shot and please help
slava [35]
The first one is 12 because if you divide 36 by 3
7 0
2 years ago
Read 2 more answers
ILL MARK BRAINLIEST WITH CORRECT <3
Alik [6]

Answer:

Step-by-step explanation:

I think the answer is 5x

8 0
2 years ago
Read 2 more answers
Given function f(x, y) = x 2 + xy + y 2 + y (1) Locate critical points (2) Classify those critical point (determine it’s local m
zvonat [6]
f(x,y)=x^2+xy+y^2+y
\nabla f(x,y)=(f_x,f_y)=(2x+y,x+2y+1)

Set both partial derivatives equal to zero and solve for x,y.

\begin{cases}2x+y=0\\x+2y+1=0\end{cases}\implies x=\dfrac13,y=-\dfrac23

The Hessian matrix (matrix of second-order partial derivatives) for this function is

H=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2&1\\1&2\end{bmatrix}\implies\det H=3>0

Now since \det H>0 for any (x,y), and f_xx=2>0 for any (x,y), it follows by the second partial derivative test that the critical point \left(\dfrac13,-\dfrac23\right) is the site of a local minimum of f(x,y). The value of the minimum is f\left(\dfrac13,-\dfrac23\right)=-\dfrac13.
4 0
2 years ago
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