Calculate the energies of the n=2 and n=3 states of the hydrogen atom in Joules per atom
1 answer:
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Given :
a. b.
c.
d.
.
To Find :
Find the most likely vale of x for each one .
Solution :
a .
Because boron have valency of 3 .
So , x = 3 .
b .
Valency of carbon is 4 .
x = 4 .
c .
Valency of nitrogen is 3 .
Therefore , x = 3 .
d .
Now ,we know valency of carbon is 4 and hydrogen is 1 .
Also , two hydrogen are already there .
So , only 2 electrons left to share .
Since , chlorine have valency of 1 .
Therefore , only 2 electrons of chlorine can connect .
x = 2 .
Hence , this is the required solution .