Please help this is for my final exam
1 answer:
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Answer:
Final speed of both the cars, V = 3.28 km/h
Explanation:
It is given that,
Mass of the railway car,
Initial speed of the railway car,
Mass of another car,
Initial speed of another car,
To find,
The speed of the coupled cars after the collision.
Solution,
It is a case of inelastic collision in which the linear momentum before and after the collision remains same. Let V is the coupled velocity of both of the cars. So,
V = 1.011 m/s
or
V = 3.28 km/h
So, the speed of the coupled cars after the collision is 3.28 km/h. Hence, this is the required solution.
Answer:
a)
b)
Explanation:
The knowable variables are the initial hight and initial velocity
The equation that describes the motion of the ball is:
If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.
a) Solving for t, we are going to have two answers
a=-16
b=64
c=80
or
<em><u>Since time can not be negative the answer is t=6.378s </u></em>
b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too
First of all, we need to find the maximum hight and how much time does it take to reach it:
at maximum point the velocity is 0
Solving for t
Now, we must know how much distance does it take to reach maximum point
So, the ball pass the top of the building on its way down at 160 ft
Solving for t
or
Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building