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Natalija [7]
3 years ago
13

What does the electron cloud model describe

Physics
1 answer:
lilavasa [31]3 years ago
5 0

<em>The electron cloud model is the current model we use to describe </em><em>atoms</em><em>. It refers to the cloud of electrons surrounding the nucleus of the atom.</em>

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Distinguish between refraction,reflection and total internal reflection
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The contrast between total internal reflection and refraction is that total internal reflection is the full underwater build with no defeat of brightness, whereas refraction is the shift in the path of a tide that is parting from one medium to another.

7 0
2 years ago
An element's atomic number is the​
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the atomic number of a chemical element (also known as its proton number) is the number of protons found in the nucleus of an atom of that element, and therefore identical to the charge number of the nucleus.

Hope this helped

8 0
3 years ago
The quantity x to be determined from the equation X=P-Q.
Softa [21]

Answer:

the correct answer will be 6.82 %that is 7%

p(1.27)-q(0.83) =x=0.44

0.02+0.01 =0.03 (maximum uncertainty)

percentage uncertainty =0.03/0.44×100 %

=6.82%

=7%

Explanation: it was d on my end

5 0
2 years ago
Which of the following is an example of acceleration? I. A car speeds up. II. A car slows down. III. A car travels in a straight
svetlana [45]
I., II., and IV. are examples of acceleration. III. isn't.
6 0
4 years ago
Oxygen at 50 lbf/in.2, 200 F is in a piston/cylinder arrangement with a volume of 4 ft3. It is now compressed in a polytropic pr
Ksju [112]

Answer:

The value of heat transfer during the process Q = - 29.49 KJ

Explanation:

Given data

P_{1} = 50 \frac{lbf}{in^{2} } = 344.7 k pa

V_{1} = 4 ft^{3} = 0.113 m^{3}

T_{1} = 200 F = 366.4 K

T_{2} = 400 F = 477.6 K

Poly tropic index n = 1.2

gas constant for oxygen = 0.26 \frac{KJ}{kg K}

From ideal gas equation

P_{1} V_{1} = m R T_{1}

Put all the values in above equation we get

⇒ 344.7 × 0.113 = m × 0.26 × 366.4

⇒ m = 0.408 kg

Heat transfer in poly tropic process is given by

Q = \frac{\gamma - n}{( \gamma - 1)( n - 1)} [ {m R (T_{1} - T_{2}  ) ]

Put all the values in above formula we get

⇒ Q = \frac{1.4 - 1.2}{( 1.4 - 1)( 1.2 - 1)} [ {m R (T_{1} - T_{2}  ) ]

⇒ Q = 2.5 × 0.408 × 0.26 × ( 366.4 - 477.6 )

⇒ Q = - 29.49 KJ

This is the value of heat transfer during the process & negative sign shows that  heat is lost during the process.

3 0
4 years ago
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