Answer:
ρ = 4407.03 kg/m³
Explanation:
The Density of a metal alloy is given by the following equation:
1/ρ = m₁/ρ₁ + m₂/ρ₂ + m₃/ρ₃
where,
ρ = density of allow = ?
ρ₁ = density of Titanium (Ti) = 4540 kg/m³
ρ₂ = density of Aluminum (Al) = 2710 kg/m³
ρ₃ = density of Vanadium (V) = 6110 kg/m³
m₁ = mass fraction of Titanium (Ti) = 90% = 0.9
m₂ = mass fraction of Aluminum (Ti) = 6% = 0.06
m₁ = mass fraction of Vanadium (V) = 4% = 0.04
Therefore,
1/ρ = 0.9/(4540 kg/m³) + (0.06)/(2710 kg/m³) + (0.04)/(6110 kg/m³)
1/ρ = 1.9823 x 10⁺⁴ m³/kg + 0.2214 x 10⁻⁴ m³/kg + 0.0654 x 10⁻⁴ m³/kg
1/ρ = 2.2691 x 10⁻⁴ m³/kg
ρ = 1/(2.2691 x 10⁻⁴ m³/kg)
<u>ρ = 4407.03 kg/m³</u>
The of melting point of gold is 1,948 degrees F and 1,064 degrees C
<span>The boiling point is 4,892 degrees F and 2,700 degrees C
Yet the numbers neutrons are 12. The number of protons is 36 and electrons is the same as protons
hope this helped :)
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Hm, this could be more than one option, but gaining electrons makes a negative charge, so
If atoms of a halogen nonmetal (Group 17) gains one electron, the atoms the have "a negative one charge".
I don’t understand your questions can you elaborate
