The answer that best suits this should be D
Answer:
a) 51.8 m, b) 27.4 m/s, c) 142 m
Explanation:
Given:
v₀ = 42.0 m/s
θ = 60.0°
t = 5.50 s
Find:
h, v, and H
a) y = y₀ + v₀ᵧ t + ½ gt²
0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²
h = 51.8 m
b) vᵧ = gt + v₀ᵧ
vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)
vᵧ = -17.5 m/s
vₓ = 42.0 cos 60.0
vₓ = 21.0 m/s
v² = vₓ² + vᵧ²
v = 27.4 m/s
c) vᵧ² = v₀ᵧ² + 2g(y - y₀)
0² = (42.0)² + 2(-9.8)(H - 51.8)
H = 142 m
Answer:
162.5 m is the distance traveled by an object.
Explanation:
Given that,
An object's constant acceleration (a) is 
.
The time (t) it traveled is 5 seconds.
The object is at rest that is "initial velocity" (u) is 0 m/s.
To find the distance traveled use the below formula,
Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.
Substitute the given values in the above formula,
s = 162.5 m
Therefore, distance traveled is 162.5 m.
Answer:
Explanation:
We can use the Einsten's relation which states the equivalence between mass and energy:
where
E is the energy
m is the rest mass of the object
c is the speed of light
By using this formula and m=2.5 kg, we can find the equivalent energy of the object:
